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3 Jan 2022
Given information
Given a square ABCD in which sides AB and AD have been divided into segments of lengths 1,2,3,...n. Thus the side of square has length n(n+1)/2 so the area is 
.
the area is also the sum of the areas of the n "gnomons" 
shown in the figure.
Step-by-step explanation
Step 1.
is square with side length 1.
so area of 
now, area of 
(area of square with side length 1+2=3) - area of
area of 
(area of square with side length 1+2+3=6)-(area of + area of 
)
= 
area of 
(area of square with side length 1+2+3+4=10)-(area of + area of + area of 
)
Single Variable Calculus: Early Transcendentals
4th Edition, 2018
Stewart
ISBN: 9781337687805
Solutions
Chapter
Section
- Problem 1
- Problem 2
- Problem 3
- Problem 4
- Problem 5
- Problem 6
- Problem 7
- Problem 8
- Problem 9
- Problem 10
- Problem 11
- Problem 12
- Problem 13
- Problem 14
- Problem 15
- Problem 16
- Problem 17
- Problem 18
- Problem 19
- Problem 20
- Problem 21
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26
- Problem 27
- Problem 28
- Problem 29
- Problem 30
- Problem 31
- Problem 32
- Problem 33
- Problem 34
- Problem 35
- Problem 36
- Problem 37
- Problem 38
- Problem 39
- Problem 40
- Problem 41a
- Problem 41b
- Problem 41c
- Problem 41d
- Problem 42
- Problem 43
- Problem 44
- Problem 45
- Problem 46
- Problem 47
- Problem 48
- Problem 49
- Problem 50