STAT1008 Study Guide - Final Guide: Central Limit Theorem, Confidence Interval, Statistical Hypothesis Testing

87 views4 pages
17 May 2018
School
Department
Course
Professor
Distribution of a Sample Proportion
ā€¢ The standard error for īŒī†ø ī‚‹ī‚•ī¶§īÆ£ļˆŗī¬µī¬æīÆ£ļˆ»
īÆ”ī‡¤
ā€¢ The larger the sample size, the smaller the SE.
Sufficiently Large n
ā€¢ The larger the sample size, the more like a normal distribution it becomes. A normal
distribution is a good approximation as long as npīµ’10 and n(1 - p)īµ’ 10.
Central Limit Theorem for ī¢–
ī·
ā€¢ īŒī†ø ~ N (īŒī‡”ī¶§īÆ£ļˆŗī¬µī¬æīÆ£ļˆ»
īÆ”ļˆ»
ā€¢ A normal distribution is a good approximation as long as np īµ’ī€ƒ10 and n(1-p) īµ’ī€ƒ10.
6.2 Confidence Interval For a Single Proportion
ā€¢ When doing inference, we donā€™t know p so substitute pĢ‚ as it is our best guess.
ā€¢ Provided the sample size is large enough so that npĢ‚ ā‰„ ī­ī¬ and n(1-pĢ‚īæā‰„ ī­ī¬, a confidence interval
can be computed by īŒī†øīµ‡ī–* ļƒ— ī¶§īÆ£ī·œļˆŗī¬µī¬æīÆ£ī·œļˆ»
īÆ”
Margin of Error
ā€¢ If we want to estimate a population proportion to within a desired ME, we should select a
sample of size
ā€¢ Neither p or pĢ‚ is known in advance. To be conservative, use p = 0.5.
ā€¢ N ā‰ˆ (1/ME)2
6.3 Test For a Single Proportion
Hypothesis Testing
ā€¢ For hypothesis testing, we want the distribution of the sample proportion assuming H0 is true.
ā€¢ To test Ho: p=po:
Test for a Single Proportion
ā€¢
ā€¢ If npo īµ’ 10 and n(1-po)īµ’ 10 , then the p-value can be computed as the area in the tail(s) of a
standard normal beyond z.
6.4 Distribution of a Sample Mean
Standard Error of Sample Means
ā€¢ The SE for ī”ī’§ = ī°™
īŽ¾īÆ”
ā€¢ The larger the sample size (n), the smaller the SE.
Central Limit Theorem for Sample Means
ā€¢ If n is sufficiently large:ī€ƒ
ā€¢ A normal distribution is usually a good approximation, as long as nīµ’ī€ƒ30.
The Distribution of Sample Means Using the Sample Standard Deviation
ā€¢ Usuallī‡‡, ī‡e doī…¶ā€™t kī…¶oī‡ the populatioī…¶ SD
ļ³
, so estimate it with the sample SD, s.
n=z* /ME
( )
2
p(1-p)
SE
=
p
0
(1
-
p
0
) / n
z=p-p0
p0
(1
-p0
) /
n
find more resources at oneclass.com
find more resources at oneclass.com
Unlock document

This preview shows page 1 of the document.
Unlock all 4 pages and 3 million more documents.

Already have an account? Log in

Document Summary

Sufficiently large n: the larger the sample size, the smaller the se, the larger the sample size, the more like a normal distribution it becomes. A normal: the standard error for is (cid:4666)(cid:2869) (cid:4667) distribution is a good approximation as long as np 10 and n(1 - p) 10. Central limit theorem for : ~ n (, (cid:4666)(cid:2869) (cid:4667) (cid:4667, a normal distribution is a good approximation as long as np 10 and n(1-p) 10. can be computed by * (cid:4666)(cid:2869) (cid:4667) If we want to estimate a population proportion to within a desired me, we should select a sample of size n = z * /me. )2 p(1- p: neither p or p is known in advance. For hypothesis testing, we want the distribution of the sample proportion assuming h0 is true: to test ho: p=po: Test for a single proportion p - p0 z = p0 (1- p0 ) / n standard normal beyond z.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers

Related textbook solutions

Related Documents

Related Questions