CAD-8104 Lecture 14: CHEM2426HOMEWORKSOLUTIONS7

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17 Jun 2020
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CHEM 2426 HOMEWORK SOLUTIONS
2N0(g)+0, (8)0 2NOr (g) For this reaction He =
(2x1)(2 + I)
But we know K, = Kc • (RT)444 Here K0 =
6.9=104 t = 227°C = (273+227)K =500K
R=0.08206 liter. atrehnol.K K, K, • ( /27)-' Since
He= _I (6.9x10') (0.082060500Y
IK, =1.68=104 0 1.7=10
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