MATH 1104 Midterm: MATH 1104 Term Test 3 Winter Spring

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1 Oct 2018
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MATH 1104 Full Course Notes
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Math1104f - test 3 ( feb 25, wednesday, 11:35 am - 12:25 pm) Part 1: multiple choice (no partial marks), circle the correct answer (cid:110) (cid:111: (true/false) (2 points) let (cid:126)0 r3. Answer: t rue: (true/false) (2 points) let a be a 4 4 matrix. If a is not invertible, then dim n ula 1. Answer: t rue: (2 points) let a = [v1 v2 v3 v4] = (cid:34) (cid:35) Which of the following can not be a basis of cola? (a) {v1, v3} (b) {v2, v4} (c) {v3, v4} (d) {v1, v2} Answer: (d: (2 points) (at b) 1 = (a) (at ) 1b 1 (b) b 1(a 1)t (c) a 1(bt ) 1 (d) (bt ) 1a 1. Answer: (b: (2 points) let (cid:126)a = (cid:34) (cid:35) (cid:34) (a) 1 0 0 | 1 1 0. X1 x2 x3 (3) let (cid:126)x =

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