BIOL-2011EL Study Guide - Final Guide: Vicia Faba, Null Hypothesis, Ploidy
8 Jan 2018
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0342483: the broad bean vicia faba, has a haploid number of 6. The total chromosome combination = 26 = 64 (1/64). There would be a 1. 56% chance of unique chromosomes from one parent: an f1 result gives you 80 brown and 40 white offspring. You suspect a dominant- recessive pair of alleles and a 3:1 ratio. Justify this hypothesis with the method of support (test of goodness of fit) X2 = 4. 444 df = [n 1] = [2 1] = [1] With an x2 value of x2 = 4. 444 and a df = 1, we reject the null hypothesis (p . 0. 05: a genetic disorder characterized by falling asleep in genetics lecture classes is known to be 20% penetrant. All the 90 students in a genetic class are homozygous for this gene.
