CHEM 120 Study Guide - Final Guide: Boiling Point, Pennsylvania Route 100, Mole Fraction
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CHEM 120 Full Course Notes
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Some data and equations that may be useful. 1 atm = 101. 3 kpa = 760 torr = 760 mmhg. Pressure at normal boiling point of a pure liquid is 1 atm. 1 mol of gas at 1 atm and 0 c occupies 22. 4 l. 1 bar = 100,000 pa = 100 kpa. Mole fraction of molecule a: a = na/ntot. M = molarity (mol. l-1) m = molality (mol. kg-1) P1v1/n1t1 = p2v2/n2t2 d = mp/rt m = mpv/rt. First order: [a] = [a]0 e-kt where k = 0. 693/t1//2. Second order: 1/[a] = 1/[a]0 + kt k = ae-ea/rt ln(k2/k1) = -ea/r{(1/t2) (1/t1)} : ln(p2/p1) = h/r(1/t1 1/t2) this eqn. applies to bo th vapor pressure (where h = hvap) and sublimation (where h = hsub). Hfus = hliquid - hsolid; hsub = hfus+ hvap. For ah + h2o = a- + h3o+, ka = [a-][h3o+]/[ah] For b + h2o = bh+ + oh-, kb = [bh+][oh-]/[b]