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EXAM Preparation Package PHYSICS 1B03

45 Pages
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Department
Physics
Course Code
PHYSICS 1B03
Professor
Karen Hughes

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McMaster SOS: Students Offering Support
1B03 Physics, Mechanics and Waves
Review Package
Thank you for your support. If interested in getting involved as a
volunteer with McMaster SOS, contact info@mcmastersos.com
Tutor: Dhruvin Hirpara
Kinematics, Motion Diagrams, Vectors
Vector quantity – A quantity that specifies a magnitude as well as a direction
Scalar quantity – A quantity that specifies just the magnitude
Distance – the physical distance traveled by a particle
Displacement – the difference in the final position and the initial position of the particle
Speed – The distance traveled per unit time (speed = total distance/total time) – a scalar quantity
Velocity – The change in displacement with respect to time. (ie. v = a vector quantity
Acceleration a vector quantity
Kinematic Equations – relates velocity, acceleration, time and displacement (ONLY IF acceleration is constant):
v final = v initial + at OR a = vfinal – vinitial / t
d = (vinitial)(t) + 0.5at2 final - initial
(vfinal)2 = (vinitial)2 + 2ad
The acceleration due to gravity ag = 9.80 m/s2
The position vs time graph, velocity vs time graph and acceleration vs time graph are related:
The slope or derivative of the position vs time graph is
the velocity vs time graph. And the derivative of the
velocity is the acceleration vs time graph.
0 – tA

v is therefore a straight increasing line
a t is therefore a straight positive line
tA - tB
is increasing but at a constant rate
v is therefore a straight positive line
a is therefore a straight line at zero
tB - tC
is increasing but at a decreasing rate
v is therefore a straight decreasing line
a is therefore a straight negative line
tC - tD

v is still a straight decreasing line but touches 0 at tD
a is still a straight negative line
tD - tE

v is a straight decreasing line
a is a straight negative line until tE
tE - tF

v starts to increase but is still negative until tF
a spikes to a positive straight line then returns to 0
Motion Diagrams
The interval of time is the same for each new added picture of the car (eg. The first car is at t =0 sec, the second car is at t =
1 sec, the third car is at t =2 sec and so on).
In figure (a) the space between each car is the same and since the time intervals are the same, the velocity (which =
displacement/time) is constant.
In figure (b) the distance between each car is getting larger, so the velocity is increasing. The acceleration of the car (which
is defined as the velocity/time) remains constant and IN THE SAME DIRECTION as the velocity (because the change in
velocity is positive).
In figure (c) the distance between each car is getting smaller, so the velocity is decreasing. The acceleration remains
constant however this time it’s in the opposite direction of the velocity because the change in velocity is negative.

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Description
McMaster SOS Students Offering Support1B03 Physics Mechanics and WavesReview Package Thank you for your support If interested in getting involved as a volunteer with McMaster SOS contact infomcmastersoscomKinematics Motion Diagrams VectorsVector quantityA quantity that specifies a magnitude as well as a direction Scalar quantityA quantity that specifies just the magnitude Distancethe physical distance traveled by a particle Displacementthe difference in the final position and the initial position of the particle SpeedThe distance traveled per unit time speedtotal distancetotal timea scalar quantity VelocityThe change in displacement with respect to time ie v a vector quantity Acceleration a vector quantityKinematic Equationsrelates velocity acceleration time and displacement ONLY IF acceleration is constantv v atORavv tfinal initialfinalinitial2dvt05at initialfinalinitial22vv2ad finalinitial 2 The acceleration due to gravity a980 msg The position vs time graph velocity vs time graph and acceleration vs time graph are relatedThe slope or derivative of the position vs time graph is the velocity vs time graph And the derivative of the velocity is the acceleration vs time graph 0tA v is therefore a straight increasing line a t is therefore a straight positive line tt ABis increasing but at a constant rate v is therefore a straight positive line a is therefore a straight line at zero tt BCis increasing but at a decreasing rate v is therefore a straight decreasing line a is therefore a straight negative line t t C D v is still a straight decreasing line but touches 0 at t Da is still a straight negative line ttDE v is a straight decreasing line a is a straight negative line until t Ett EF v starts to increase but is still negative until tFaspikes to a positive straight line then returns to 0Motion DiagramsThe interval of time is the same for each new added picture of the car eg The first car is at t 0 sec the second car is at t1 sec the third car is at t 2 sec and so onIn figure a the space between each car is the same and since the time intervals are the same the velocity whichdisplacementtime is constantIn figure b the distance between each car is getting larger so the velocity is increasing The acceleration of the car which is defined as the velocitytime remains constant and IN THE SAME DIRECTION as the velocity because the change in velocity is positiveIn figure c the distance between each car is getting smaller so the velocity is decreasing The acceleration remains constant however this time its in the opposite direction of the velocity because the change in velocity is negative
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