STAT 2500 Final: Stats 2500 finals notes
11 Dec 2015
School
Department
Course
Professor
Document Summary
I=1 n n: describes how data are distributed. Mode: the value that occurs most often: skew = symmetry. Data= {0, -3, -8, 4, 3, 8, -1} 2 n xi2) 1 ( i=1 n ( xi x )2 n. Chebyshev"s theorem (1 1 k2) 100 k standard deviationinterval. Chebyshev (-1,1) 0% (-2, 2) 75% (-3, 3) 89% Compound event: more than one outcome of sample points . Can only be the section where the red and blue section meet. P ( a b)=p ( a)+p (b ) p( a b) P (b a)=p ( bia ) p( a ) E [x ]= = x p ( x) expectedvalue x x ( 2 )= . X2 p ( x) x p(x) E [x ]= = x xp ( x)=(0)( 1 x 2 p( x)=(0. 25 )( 1. X2 p (x) n x p(x)=p {x b+x}= p. If n-25, and the population is normal, with =8 , =2.
