Quiz 2 cheat sheet.docx

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Queen's University
Mechanical and Materials Engineering Courses
MECH 230
Gabriel Ciccarelli

Liquid – Vapour PV=MRT PV=nRT Pgauge=Pabs-Patm Pv=RT Obj100 (UNDER DOME) P1= P + 2gL x=mgmg-mf W=V1V2PdV v=vf+xvg-vf Obj101 Polytropic Process: n≠1: W=P2V2-P1V11-n u=uf+xug-uf n=1: W=P2V2lnV2V1 W=P1V1lnV2V1 h=hf+xhg-hf n=0: const. P: W=PV2-V1 T2T1=P2P1n-1n=v1v2n-1 const. V: W = 0 W=MR(T2-T1)1-n Work by or Heat to the system is positive cpT=cvT+R Work on or Heat from the system is negative Compressed liquids: If P is small, cpT=cvT+R u(P,T) ~ u(f) kT=cpcv Adiabatic: Q = 0 v(P,T) ~ vf(T) cvT=RkT-1 ∆E=-W cp(T)=kTRkT-1 Isothermal: T = const; * h(P,T) = h(f) + v fP-P sat)) Other ΔU = 0, unless state is changing E2– E 1 Q – W Obj102 ∆E=∆KE+∆PE+∆U=Q-W 12mv22-v12+mgh2-h1+12kx22-x12+mT1T2cvdT=Q-W ∆U=U2-U1=Q-W h=u+Pv Wcycle=Qcycle Power CycleW cycle Q in out Refrigeration Cycle W cycle Q >V ): 1 Turbine Mass flux: Transient Control Volume Analysis (1 inlet or 1 exit) ; ; for reservoir flow into rigid tank, initially a Volumetric Flow Usually we can neglect KE: vacuum. 2ndLaw of Thermodynamics Rate: Clausius Statement: It is impossible for a system to
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