ASC 402 Study Guide - Quiz Guide: Thermostat, Mass Flow Rate, Reversing Valve

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A stream of humid air is heated by a heating coil. At the inlet of the coil, the drybulb and wet-bulb temperature of the humid air are 5 oc and 3 oc respectively. The heating capacity of the heating coil is 46. 5 kw. Show the air handling process in the psychrometric chart. 2 t2dry > 35 c h1 = 15 kj/kgda. Q = 46. 5kw h2 = 51 kj/kgda h2 = 45 kj/kgda given. Q = 46. 5 kw t1dry = 5 c t1wet = 3 c t2dry > 35 c find h1 = ? h2 = ? ma = ? mb = ? from chart : t1dry = 5 c t1wet = 3 c. H2 = 45 kj/kgda find h find m from chart : assume t2dry = 40 c : 46. 5 kw = m (45 kj/kgda- 15 kj/kgda ) 46. 5 kw = m (51 kj/kgda- 15 kj/kgda ) m = 46. 5 kw 30 kj/kgda.

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