COE 758 Final: COE758 - Fall 2000 Final (Solutions)

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Ele 758 final examination 2000: answers and solutions. Word 0" word 1" word 2" word 3". Miss rate = [5 (misses) / 20 (total memory references)]* 100% = 25% Show the final content of cache using the content of sdram (4) Question # 1. 2: determine block size (n) in bytes if miss penalty tm = taddr (sdram) + nxtw: Show calculations: tav = rhit x th + r miss x t miss = R hit x th + (1 rhit) x [taddr (sdram) + n x tw ] N = [ t av r hit x th (1 r hit)x taddr (sdram)] / (1- rhit) x tw = = [21. 5 ns 0. 95 x 10 ns x 10 ns (1 0. 95) x 80 ns ] / (1 0. 95) x 10 ns = 16 words = 16 x 4 bytes = 64 bytes: determine number of cache entries - n entr = __4096__________

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