MEC 626 Study Guide - Final Guide: Xg Technology, A158 Road, Normal Force

• School: Ryerson University
• Department: Mechanical Engineering
• Course: MEC 626
• Professor: Jun Cao

Document Summary

Ra = 2 sin 60 = 1. 732 kn ans. Rb = 2 sin 30 = 1 kn ans. Ma = 0 h = 4. 5 (cid:1) tan 30. 9re 7. 794(400 cos 30) 4. 5(400 sin 30) = 0. Ra (d) step 1: find ra and re. Fx = 0 rax + 400 cos 30 = 0 rax = 346. 4 n. Fy = 0 ray + 400 400 sin 30 = 0 ray = 200 n (cid:2) Step 2: find components of rc on link 4 and rd (cid:1) 400(4. 5) (7. 794 1. 9) rd = 0 rd = 305. 4 n ans. (cid:1) Fx = 0 ( rc x)4 = 305. 4 n. Fy = 0 ( rcy)4 = 400 n (rcy)4. Step 3: find components of rc on link 2. Fx = 0 (rcy)2 (cid:1) (cid:1) ( rc x)2 + 305. 4 346. 4 = 0 ( rc x)2 = 41 n ( rcy)2 = 200 n.