CHEM101 Study Guide - Diamagnetism, Quadruple Bond, Paramagnetism
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CHEM101 Full Course Notes
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Last time we sketched the he2 mo energy diagram . Note that we can ignore the 1s and 1s* as they cancel out. Thursday, oct 16, 8am thursday, oct 23, 8am. 2 = 1 stable unpaired e paramagnetic = attracted to a magnet. Note that 2s and 2s* cancel out and can be ignored. Note that the pz + pz bonding and pz pz antibonding. Mos are not shown on this figure but they also contribute a 2p and 2p* mos. The yellow color seen when burning hydrocarbons is thought to be due to c2. Trying to explain the existence of c2 with previous models fails. Nve = 2 x 4 = 8 e . : c=c: quadruple bond no octets no octets. However the existence can be explained using mo theory. 2 = 2 stable all e paired diamagnetic unpaired e paramagnetic. Note that the mo order is different from that of n2.