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Study Guides for MATH100 at University of Alberta

Calculus I

MATH100 Study Guide - Final Guide: Negative Number, Nules, Approximation Error
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MATH 100 Calculus I Final Exam Study Guide (Part 2) University of Alberta Fall 2015 MATH 100 Lecture 12 Limits to Infinity and Continuous Functions SQUEEZE THEOREM. Theorem: If then . f(x) lim=0 f(x) lim=0 xx Suppose that ...

Mathematics
MATH100
Meymanat Farzamirad
MATH100 Midterm: MATH100 Midterm 2001 Fall
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Mathematics
MATH100
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MATH100 Study Guide - Midterm Guide: Mean Value Theorem
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Solutions for Math 100 2003 Midterm PROBLEM 1: Evaluate the limits (a) lim 1 4 and (b) lim j3x 1j j3x + :j x!2 x 2 x 4 x!0 x 1 1 Solution for (a): The testgiv0s 0 = ? so further work is needed. 1 4 x + 2 4 x 2 1 1 lim 2 = ...

Mathematics
MATH100
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MATH100 Midterm: MATH100 Midterm 2001 Fall Solutions
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AO ff WA,+ 5wNAW5c 6ww 2ff gihi?@i i@U Lu i uL**L?} hitTiU L E)L ?ii_ ?L t4T*u)G E@ dSo s E e dULtE n tiUEoc t?E@ EM dSo s E c EU dSo s E *4 @ @?E n ULtE 5L*L?G E@ e s E dULtE ntiUEone d t?E SntiUE @?Eo n EM ! d@?E ...

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MATH100
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MATH100 Study Guide - Midterm Guide: Asymptote
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Solutions for Math 100 2006 Midterm 1. Each limit exists and is given by (a) p sin(x 1) sin(x 1) 1 + 3x + 2 x!1mp = x!1 p p 1 + 3x 2 1 + 3x 2 1 + 3x + 2 sin(x 1) 4 sin(x 1) 4 = 4 lim = lim = : x!1 (1 + 3x 4) 3x!1 x 1 3 p (...

Mathematics
MATH100
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MATH100 Study Guide - Midterm Guide: Intermediate Value Theorem
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MATHEMATICS 100 - MIDTERM EXAMINATION Date: February 16, 2006 Time: 80 Minutes Lecturer: Professor GE Swaters SURNAME: GIVEN NAMES: PLEASE PRINT ID Number: INSTRUCTIONS: Answer all questions Unsubstantiated work may not re...

Mathematics
MATH100
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MATH100 Quiz: MATH100 Midterm 2007 Winter Solutions
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Solutions for Math 100 2007 Midterm 1. Each limit exists and is given by (a) 1 x 4 3 3 limp = = : x!1 x 8 7 7 (b) x x 1 lim = lim = : x!0 jx 1j jx + 1j x!0 1 x x 1 2 2. In order that the two curves be orthogonal it is nece...

Mathematics
MATH100
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MATH100 Study Guide - Midterm Guide: Intermediate Value Theorem
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MATHEMATICS 100 - MIDTERM EXAMINATION Date: February 15, 2007 Time: 80 Minutes Lecturer: Professor GE Swaters SURNAME: GIVEN NAMES: PLEASE PRINT ID Number: INSTRUCTIONS: Answer all questions Unsubstantiated work may not re...

Mathematics
MATH100
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MATH100 Study Guide - Final Guide: Even And Odd Functions, 4Dx, Maxima And Minima
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solutions to the April 2000 math 100 final 1. Let p(x) be the ticket price, x the number of seats sold, and r (x) the revenue. (a) Assuming the linear relationship p = a + bx, the constants a and b are determined by a + b ...

Mathematics
MATH100
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MATH100 Study Guide - Final Guide: Riemann Sum
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MATHEMATICS 100 - FINAL EXAMINATION Date: April 26, 2006 Time : 120 Minutes Instructor: Professor G E Swaters 1. Evaluate the following integrals: Z 1 ex (a) dx 1 2 + 2e + e2x Z 2 sec( 1+) p 3 3 (b) 1 + cos ()tan + sin () ...

Mathematics
MATH100
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MATH100 Midterm: MATH100 Midterm 2000 Fall Solutions
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solutions to the february 2000 math 100 midterm x + 1 1. HAs and VAs for f(x) = . For the VAs we observe (x + 1)(x 2) 2 2 x + 1 x + 1 lim+ = 1 or lim = 1; x!1 (x + 1)(x 2) x!1 (x + 1)(x 2) x + 1 x + 1 lim = 1 or lim = 1: x...

Mathematics
MATH100
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MATH100 Study Guide - Final Guide: Even And Odd Functions, The Sketch, Riemann Sum
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Solutions for Math 100 April 2007 Final 1. (a) Introducing the substitution u = 1=x, leads to 1 + du = 2dx and that x ! 1 () u = 0 and x = 0 () u ! 1; x 1 0 Z x Z =) e dx = e du = e ]0 = 1: x2 1 0 1 (b) Observing that the ...

Mathematics
MATH100
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MATH100 Study Guide - Final Guide: Even And Odd Functions, Scilab, The Sketch
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Solutions for Math 100 2003 Final 1. Evaluating the integrals (a) The substitution x = u =) dx = 2udu, gives Z Z dx du 1 1 p p = 2 2 = 2tan (u) + C = 2tan x + C: x(1 + x) 1 + u (b) Observing that the integrand is an odd fu...

Mathematics
MATH100
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MATH100 Study Guide - Final Guide: Maxima And Minima
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solutions to the April 2001 math 100 final 1. (a) Let u = e =) du = e dx, hence Z Z x Z dx e du x x = 2x dx = 2 e + e 1 + e 1 + u = arctan(u) + C = arctan(e ) + C: 2 (b) Let u = x =) du = 2xdx, hence Z1 Z x2 1 u2 xe dx = e...

Mathematics
MATH100
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