MATH100 Study Guide - Midterm Guide: Mean Value Theorem
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MATH100 Full Course Notes
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4 x2 (cid:0) 4(cid:19) and (b) lim x!0(cid:18)j3x (cid:0) 1j (cid:0) j3x + 1j x (cid:19) : Solution for (a): the (cid:147)test(cid:148)gives 1 x!2(cid:18) 1 (a) lim x (cid:0) 2 (cid:0) x2 (cid:0) 4(cid:19) = lim (cid:19) = lim x!2. 4 lim x (cid:0) 2 (cid:0) x!2(cid:18) 1 x!0(cid:18)j3x (cid:0) 1j (cid:0) j3x + 1j lim x. 0 = ? so further work is needed. 0 (cid:0) 1 x + 2 (cid:0) 4 x2 (cid:0) 4. 0 = ? so further work is needed. x (cid:0) 2 x2 (cid:0) 4. 4 x!0(cid:18)(cid:0) (3x (cid:0) 1) (cid:0) (3x + 1) x (cid:19) = lim x!0 (cid:0)6x x. Problem 2: determine the horizontal and vertical asymptotes for. For the vertical asymptotes we need to solve px2 (cid:0) 2x (cid:0) x = 0 ()px2 (cid:0) 2x = x () x2 (cid:0) 2x = x2 =) x = 0: