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Study Guide

BIOL 239- Final Exam Guide - Comprehensive Notes for the exam ( 36 pages long!)

36 pages83 viewsSpring 2018

Department
Biology
Course Code
BIOL239
Professor
Barbara Moffatt
Study Guide
Final

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UW
BIOL 239
Final EXAM
STUDY GUIDE
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Drosophila Assignment
Akashdeep Suri (20618733)
Part A
Hypothesis
Hypothesis is gene for ruby eyes is x-linked recessive, and gene for curved wings is autosomal
recessive
Let Xw+ represent the dominant wild-type X-chromosome that carries allele for wild-type wing
shape
Let Xw represent the recessive (mutated) allele producing curved wings
Let e+ represent the wild-type eyes, which are dominant to e, which represent the ruby eyes
P Generation
e+e+Xw+Xw+ crossed with eeXwY
Xw+ Xw+
Xw Xw Xw+ Xw Xw+
Y Xw+Y Xw+Y
Ratios: There is a ratio of 1 that the female offspring will have wild type wing shape
There is a ratio of 1 that the male offspring will have wild type wing shape.
e+ e+
e e+e e+e
e e+e e+e
Ratios: There is a ratio of 1 that all offspring will have wild type eye colour.
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F1 Generation
e+eXw+Xw crossed with e+eXw+Y
Xw Xw+
Xw+ Xw Xw+ Xw+ Xw+
Y XwY Xw+Y
Ratios: There is a phenotypic ratio of 1 that the female offspring will have wild type wing shape
There is a phenotypic ratio of 1:1 that the male offspring will have mutant or wild type
wing shape.
e+ e
e+ e+e+ e+e
e e+e ee
Ratio: There is a phenotypic ratio of 3:1 that all offspring will have wild type eyes versus ruby
eyes.
F2 generation from given data
Phenotype
Genotype
Curved wings, male
225
e+_XwY
Wild type, males
698
e+_Xw+Y
Ruby eyes, curved wings, males
241
eeXwY
Ruby eyes males
694
eeXw+Y
Curved wings, females
460
e+_XwXw
Wild type, females
1321
e+_X+w_
Carrying out the Chi Square (x^2 ) test for female wings :
Phenotype
Observed (O)
Expected (E)
(O-E)^2
(O-E)^2 / E
Curved wings
(ee)
460
440.25
390
0.89
Wild type wings
(e+ __)
1321
1320.75
0.0625
0.000047
Total
1761
1761
Chi square=
0.89
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