STAT230 Study Guide - Midterm Guide: Decimal Mark, Blood Test

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14 Nov 2012
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Short Solutions to Stat 230 Test 2, Feb 1, 2012
1. An irregular die is loaded to give the probabilities P({1}) = 0.2, P({2}) = 0.4, P({3}) = P({4}) =
P({5}) = P({6})=0.1. The die is rolled 8 times and results from different rolls are independent.
Find the probability that
[2] (a) A = “1 does not occur”
P(A) = (1 0.2)8= 0.88= 0.1678
[1] (b) B = “2 does not occur”
P(B) = (1 0.4)8= 0.68= 0.0168
[2] (c) C = “neither 1 nor 2 occurs”
P(C) = P(AB) = (1 0.20.4)8= 0.48= 0.00066
[2] (d) D = “both 1 and 2 occur”
P(D) = P(¯
A¯
B)=1P(AB) = 1 [P(A) + P(B)P(AB)] = 1 (0.88+ 0.680.48) = 0.8161
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