BIO 3170 Study Guide - Midterm Guide: Phosphodiester Bond, Pyrophosphate, Hydrolysis
Leture Ojetives DNA Repliation
1. Explain why the reaction of DNA synthesis is favorable on the basis of energy
Reactants: DNA + NTP
• Start of with a DNa strand where a single nucleotide, NTP, will be added at a time.
Products: DNA-NMP + PPi
• The added nucleotide only has one phosphate
• Pyrophosphate is also generated as a product
The first release of energy is from the hydrolysis of the bond between the sugar of the activated
nucleotide and the alpha phosphate
o The hydrolysis of this bond will generate energy
The second release of energy comes from the hydrolysis of PPi into 2 Pi.
Summary: the reaction is favorable mostly because the release of energy that comes from
pyrophosphate hydrolyzing into 2 inorganic phosphates
2. During the reaction of DNA synthesis, why are the nuclotides added in the form of triphosphates
and not in the form of di or mono phosphates?
DNA + NTP → DNA-DMP + PPi
This reaction is favorable because PPi → 2Pi.
• Pyrophosphyate is hydrolyzed into two inorganic phosphates. The reaction is driven to the
right (formation of products).
• Le Chetalie’s piiple alls fo eplaeet of a podut eig degaded
o Generating my phosphatases
o Formation of the phosphodiester bond to drive the elongation of the DNA chain
Re write reaction
DNA + NDP → DNA-DMP + Pi
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• In the casae where we use a Diphosphate instead of a triphosphate we end up producing
1Pi
• Pi cannot further hydrolyze and drive the reaction to the products thus slows down
elongation of the chain.
Re write reaction
DNA + NMP → DNA-DMP + PPi
• We can generate and elongation of the DNA chain but a very low efficients
DNA + NP →
• Addition of a nucleotide with no phosphates
• No product form
• Phosphodiester bond cannot even be created becayse no phosphate is present
Summary: So the only optimal reaction/ efficite/ generationi of energy for the DNA chain to by
elongated by DNA polymerase is the one in which nucleotids are added in the activated form of
triphosphate
3. During epliatio h is DNA elogated fo 3’ ed ad the dietio is 5’→ 3’
• Coetioall, elogatio ous at the 3’ ed
o 1st reason: enzyme strucuture of DNA polymerase
▪ DNA polymerase is responsible for the catalysis of phosphodiester bonds on
the backbone allows for only positioning and elongation at the 3’OH end
▪ Remember: Reaction where DNA + free activated triphosphate allows for
elogatio at the 3’d
▪ Note: the addition of nucelotides would also occur because there are 3
phosphates i the 5’ ed ad a fee 3’OH goup o the fee atiated
triphosphate
• Difference: pyrophosphate would come from the DNA chain and
not the activated ucleotide whereas in elongation of the 3’OH end
the pyrophosphate comes from th activated nucleotide
o 2nd reason: Proof reading activity of DNA polymerase
▪ 1. A mismatch error occurred in the newly synthesized DNA
▪ 2. DNA polymerase can remove the incorrectly paired nucleotides
• A 3’OH – the monophosphate formed can be removed and the
3’OH ith o phosphate ill e egeeated & aailale fo the
addition for the correct addition of nucleotide and the creation of
the phosphodiester bond.
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• B) 5; END: There will be a removal of the incorrect nucleotide at the
5’ ed ut o it ill eoe the phosphates that ee ogioall
attathced to the incorrectly paried nucleotide. This leaves us with a
5’ ed that is uale to udego pope DNA atalsis eause of
the absence of the triphosphate and the presence of a
monophostphate.
o In trying to add the correct nucleltodie, there is no high
energy bond cleavages and no energy released during the
formation of phosphodiester bonds and therefore not
favorable.
4. Explain the mechanisms of replication of the DNA lagging strand.
• Orientation of the replication fork
o If the fork is moving to the R→
▪ Picture:
o If the fork is moving the the L →
▪ Picture
1st step: addition of the RNA primer(9 bp long) synthesis by DNA primase
2nd: DNA polease il eted ad elogate fo the RNA pie 3’OH Okazaki fagets
3rd: RNase H will digest the RNA primers & DNA polymerase will synthesize new strands
4th: DNA igase sticketes the emtpt spots
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Document Summary
Le(cid:272)ture o(cid:271)je(cid:272)tives dna repli(cid:272)ation: explain why the reaction of dna synthesis is favorable on the basis of energy. Reactants: dna + ntp: start of with a dna strand where a single nucleotide, ntp, will be added at a time. Products: dna-nmp + ppi: the added nucleotide only has one phosphate, pyrophosphate is also generated as a product. The first release of energy is from the hydrolysis of the bond between the sugar of the activated nucleotide and the alpha phosphate: the hydrolysis of this bond will generate energy. The second release of energy comes from the hydrolysis of ppi into 2 pi. This reaction is favorable because ppi 2pi: pyrophosphyate is hydrolyzed into two inorganic phosphates. The reaction is driven to the right (formation of products). Le chetalie(cid:396)"s p(cid:396)i(cid:374)(cid:272)iple (cid:272)alls fo(cid:396) (cid:396)epla(cid:272)e(cid:373)e(cid:374)t of a p(cid:396)odu(cid:272)t (cid:271)ei(cid:374)g deg(cid:396)aded (cid:271)(cid:455: generating my phosphatases, formation of the phosphodiester bond to drive the elongation of the dna chain.