ELG 2138 Study Guide - Final Guide: Voltage Divider, Dependent Source, Voltage Source
29 Nov 2018
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Problems on voltmeters and ammeters, independent and dependent sources. R=10ohm, voltage source delivers :6w a)vr=:50v, vm=62v, b)powers for vs is :24w, for cs is 124w, for. R is :100w, total is 0w. r=4 v/a. R=2 ohm, a= :4 v/a. Series resistances and voltage division parallel resistances and current division. Series voltage sources and parallel current sources. The power supplied by element b is 12 w, and by f is 13w. The power absorbed by 4ohm is 16w, by 6ohm is 24w, by 8 ohm is 8w. Has been solved in the tutorial session. i1=0. 5a, im=0. 25a i1=1/3 a, vm= 8v a)12v, b)0. 9w, c)r=15ohm, d) r=30ohm ia=2a, vm =5v. V3=3v, i=1a i1=:2a, i2=:3a, i=i1:i2=1a!this equation shows the direction of i1 and i2. Power by 8v:vs is 17w, 3v:vs is :6. 375w, 3a:cs is :2. 25 w, I don"t have the solution for this in my version. i= 1a, v=8v, req=12ohm. If rp=2000ohm, then r1= 6000ohm, r2= 4000ohm. Vab=~200mv, let v=16 then r=5ohm then p=25. 6w.
