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Midterm

1322Midterm1AS14Solution (1).pdf

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Department
Mathematics
Course Code
MAT1322
Professor
All

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Description
MAT13223X Solution to Midterm 1ASummer 2014 Solution to Midterm Examination 1 version A MAT 13223X Summer 201413 marks Use the definition of improper integrals to find the value of improper integral 31dx 236x 3311Solutioni limdxdx2a2a3636xx u3x6 u3 Use variable substitution33331111123limlimlim2dxdxduu 236aa36ua222aaa3333636xxuxdx diverges 2 3 marksUse the comparison test to show that improper integral3121x 1xx113312SolutionSince 2x12x Since dxxdx33112x22x212xxxdiverges improper integraldiverges dx3121x 23
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