ANT203H5 Study Guide - Midterm Guide: Allele Frequency, Genotype Frequency

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17 Oct 2013
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Let cr represent non-crinkly hair q2 = 150/600 q2 = 0. 25. He allows the remaining animals to breed freely. Calculate the genotype frequencies in the zygotes in the next generation. w= 1 w= 0. 8 w=0. 6. Aa 0. 48 aa 0. 36 p(aa) = [(0. 16)(2)(1) + (0. 48)(1)(0. 8)] / [(0. 16)(2)(1) + (0. 48)(2)(0. 8) + (0. 36)(2)(0. 6)] p(aa) = [(0. 36)(2)(0. 6) + (0. 48)(1)(0. 8)] / [(0. 16)(2)(1) + (0. 48)(2)(0. 8) + (0. 36)(2)(0. 6)] Aa = 2pq = 2(0. 46)(0. 54) = 0. 4968 aa = q2 = (0. 54)2 = 0. 2916: coat color in the rabbit is determined by three alleles: the c allele (albino), which is. 0. 2 recessive to cch allele (chinchilla coat), which in turn is recessive to c (the allele for full coat color). In a randomly mating population of rabbits the following allele frequencies were determined: R p2 + q2 + r2 + 2pq + 2pr + 2qr. Normal coat = p2 + 2pq + 2pr = 36% Chinchilla = q2 + 2qr = 60%