chem assignment 5.docx

2 Pages
273 Views
Unlock Document

Department
Chemistry
Course
CHM110H5
Professor
Thottackad Radhakrishnan
Semester
Fall

Description
NAME: YVONNE EIFEDIYI STUDENT NO:1001045102 LAB SECTIONA101 DATE : NOVEMBER 22 ND 2013 ASSIGNMENT 5 A. Solar energy = 1 kW m 2 1 mol of C 12O22 5110 kJ 20 kg C 12O22 51142 mol C H O 12 22 11 ∴ 58.42 mol C H12 22x 11 __1 mol___ = _5640 kJ_ 58.42 mol x kJ x = 329496.99 kJ of sunlight used to produce 20 kg C H O12 22 11. 20 kg/h/ha = 329496.99 kJ/(60 x 60)s/10000 m 2 = 0.00915 kJ/s/m 2 = 0.00915 kW/m (since 1 kJ/s/m = 1 kW/m ) 2 Amount of energy needed to produce C H O 12 22 11 x 100% Solar energy = 0.00915 kW/m x 100% = 0.915% of sunlight used to produce the sucrose. 1.0 kW/m 2 B. 15% efficient in converting sunlight to electricity 40 kWh/day of that electricity _1 kWh_ = 3600 kJ 40 kWh x kJ x = 144000 kJ of electricity energy needed per day 144000 kJ = 0.15 x x (where x represents the solar energy) x = 960000 kJ of solar energy 960000 kJ = 120000 kJ/h 8 h 120000 kJ/h is needed for conversion. 1 kW = 3600 kJ/h 2 2 We also know that I kJ/s/m = 1 kW/m ∴ 1 kW/m = 3600 kJ/h/m 2 Surface area = __number of kJ/h__ 2
More Less

Related notes for CHM110H5

Log In


OR

Join OneClass

Access over 10 million pages of study
documents for 1.3 million courses.

Sign up

Join to view


OR

By registering, I agree to the Terms and Privacy Policies
Already have an account?
Just a few more details

So we can recommend you notes for your school.

Reset Password

Please enter below the email address you registered with and we will send you a link to reset your password.

Add your courses

Get notes from the top students in your class.


Submit