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# chem assignment 5.docx

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Department
Chemistry
Course
CHM110H5
Professor
Semester
Fall

Description
NAME: YVONNE EIFEDIYI STUDENT NO:1001045102 LAB SECTIONA101 DATE : NOVEMBER 22 ND 2013 ASSIGNMENT 5 A. Solar energy = 1 kW m 2 1 mol of C 12O22 5110 kJ 20 kg C 12O22 51142 mol C H O 12 22 11 ∴ 58.42 mol C H12 22x 11 __1 mol___ = _5640 kJ_ 58.42 mol x kJ x = 329496.99 kJ of sunlight used to produce 20 kg C H O12 22 11. 20 kg/h/ha = 329496.99 kJ/(60 x 60)s/10000 m 2 = 0.00915 kJ/s/m 2 = 0.00915 kW/m (since 1 kJ/s/m = 1 kW/m ) 2 Amount of energy needed to produce C H O 12 22 11 x 100% Solar energy = 0.00915 kW/m x 100% = 0.915% of sunlight used to produce the sucrose. 1.0 kW/m 2 B. 15% efficient in converting sunlight to electricity 40 kWh/day of that electricity _1 kWh_ = 3600 kJ 40 kWh x kJ x = 144000 kJ of electricity energy needed per day 144000 kJ = 0.15 x x (where x represents the solar energy) x = 960000 kJ of solar energy 960000 kJ = 120000 kJ/h 8 h 120000 kJ/h is needed for conversion. 1 kW = 3600 kJ/h 2 2 We also know that I kJ/s/m = 1 kW/m ∴ 1 kW/m = 3600 kJ/h/m 2 Surface area = __number of kJ/h__ 2
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