# CHM110H5 Final: Assignment 2

Assignment #: 2

a)

0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1

22.15

22.2

22.25

22.3

22.35

22.4

22.45

PV as a function of P for 1.0 mol CO2 at 0°

V CO2 (L)

V Ideal Gas

(L)

Pressure (atm)

Pressure . Volume (L atm)

Figure 1: V CO2 (diamond); X is pressure with the unit atm, and Y is Pressure*Volume

with the unit Latm. There is a decreasing trend in this function. As the value of P

increases, the value of PV decreases. Thus the equation, PV=22.415-0.158P. V Ideal

Gas (Square); X is pressure with unit atm, and Y is Pressure*Volume with the unit

Latm. The function is constant, as the values of P increase the value of PV remains

22.4125. Thus the equation, PV=22.415. The graph corresponds to the equation:

PV=RT+BP; where PV is the value of Y, RT is the value of the Y-intercept, B is the

slope and P is the x value. The

b) RT is the y-intercept of the above equation. When pressure is equal to 0 atm, the RT

value (y-intercept) is equal to the value of how much PV is found in the gas CO2. This

can be confirmed by determining the units of RT:

RT=

(

L atm

mol K

)

(

K

)

The K values cancel each other out, and since 1 mol is being considered the units of RT

are

RT=L atm

.

Determining the value of RT:

The ideal gas law: PV=nRT1, considering 1 mol:

Therefore, the equation becomes PV=RT. R is a constant, 0.08205 and T is given,

273K 2

PV=(0.08205

(

L atm

mol K

)

(273 K)