PSYA02H3 Study Guide - Final Guide: Ammonia, Trigonal Pyramidal Molecular Geometry, Tu Youyou

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Published on 17 Sep 2019
School
Department
Course
1
Name_______________________
Student Number_____________________
CHMB41H3
ORGANIC CHEMISTRY I
MIDTERM EXAM
October 30th, 2015, 3-4:30pm
TIME ALLOWED: 90 minutes
NO CALCULATORS ALLOWED. MOLECULAR MODELS ARE ALLOWED.
NO PAGERS OR MOBILE PHONES ALLOWED
Write in non-erasable pen. Do not use whiteout. No re-marking claims will be accepted if
these rules are broken.
WRITE YOUR ANSWERS FOR ALL QUESTIONS ON THE SPACES PROVIDED IN
THE ANSWER SHEETS ON PAGES 6-8. ONLY THE ANSWERS PROVIDED ON THE
ANSWER SHEETS WILL BE MARKED.
NO OTHER PAPER MAY BE USED IN THIS EXAM. A PERIODIC TABLE AND
ROUGH PAPER ARE PROVIDED AT THE END OF THE ANSWER SHEET.
Read through the test before you begin.
PART I.____________ (10)
PART II.
1.____________ (8)
2.____________ (14)
3.____________ (12)
4.____________ (8)
5.____________ (8)
Total Marks ________________/ 60
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2
CHMB41H First Midterm Test 1_Fall 2015
Name:
Part I (10 marks) - Multiple Choice (1 mark each) Place your answers in the boxes on the
answer sheet.
Artemisinin, also known as qinghaosu, and its semi-synthetic derivatives are a group of drugs
that possess the most rapid action of all current drugs against malaria. It was discovered by Tu
Youyou, a Chinese scientist, who won the Nobel prize in medicine on October 5, 2015, for her
discovery of Artemisinin, along with two other scientists.
Questions 1 to 4 pertain to the structure of Artemisinin, shown below:
1. How many asymmetric centers does Artemisinin contain?
(a) 7 (b) 5 (c) 6 (d) 8 (e) 10
2. The bond between atoms labeled a” and “b” is formed by overlap of which types of orbitals
on these atoms?
(a) sp2-sp3 (b) sp2-sp2 (c) sp-sp
(d) sp3-sp2 (e) sp3-sp3
3. The molecular group geometry at the O atom labeled 1” can best be described as:
(a) bent (b) linear (c) trigonal pyramidal (d) trigonal planar (e) tetrahedral
4. How many unhybridized p orbitals are on the oxygen atom labeled “2?
(a) 2 (b) 1 (c) 0 (d) 3 (e) 4
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3
CHMB41H First Midterm Test 1_Fall 2015
Name:
5. The least stable conformation of 3-bromo-2-methylpentane, viewed through the C3C4
bond:
(a) I (b) II (c) III (d) IV (e) V
6. Rank the bold-faced hydrogens for the following compounds from most acidic to
least acidic.
a) V > III > II > IV > I
b) III > V > IV > II > I
c) V > III > II > I > IV
d) V > III > I > II > IV
e) III > V > II > I > IV
7. Which compound is not a constitutional isomer of the others?
(a) I (b) II (c) III (d) IV (e) V
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