Statistical Sciences 2244A/B Study Guide - Final Guide: Binomial Distribution, Sampling Distribution, Statistical Hypothesis Testing

44 views3 pages
Stats 2244
Two sample Inference
Difference in proportions
Scenario
- Risk of breast cancer is thought to be influenced by events between age of menarche and age at
first child birth. An international study was conducted to evaluate whether the risk of breast
cancer differs for young versus old mothers. A SRS of 3099 women who were <30 y old when
they had their first child was identified; of these women, 1890 were hospitalized for breast
cancer. A SRS of 7546 women who were 30+ when they had their first child was identified. Of
these women, 7038 were hospitalized for breast cancer. All others had no history
Approximate z test for difference in p
- So this scenario deals with 2 samples: the sample of young mothers and the sample of older
mothers
- The data should be summarized with proportions bc breast cancer history is qualitative
- We use an approx. z test for a difference in proportion
- We look at null and alternate hypothesis
o H0: p1=p2
o The alternative hypothesis could be left tailed, right tailed or two tailed
- The test statistic we are dealing with is an approx. z test
- We have 2 p hat values: proportions of successes (women with breast cancer in our two
samples)
- Then we have our hypothesized value for our parameter
o Here, our parameter is the difference in proportions (p1=p2)
- In the denominator, we have the SE of the relevant sampling distribution
o Here, bc the parameter we are looking at is the difference in proportions, and the
statistic we are working with is the difference in sample proportions
o So the denominator is the estimates SD for the difference in sample proportions
- P bar is the pooled estimate of the proportion
o We are pooling (bringing together) all the successes in our two samples
o x1 and x2 are the count of number of successes in sample 1 and sample 2
o q bar is calculated using the complement (1-p bar)
- conditions:
o samples are independent (not matched pairs) to evaluate this, we have to look at the
sampling strategy
o both samples are SRS
o using normal as an approx. for an underlying binomial distribution
we need to binomial conditions to apply
if we are dealing with proportions and some success vs failure, we have 2
outcomes, fixed sample sizes, and if the rest of the conditions are valid, then the
binomial setting should apply
we need the number of successes and failtures in both sample 1 and separately
in sample 2 to be at least 5
find more resources at oneclass.com
find more resources at oneclass.com
Unlock document

This preview shows page 1 of the document.
Unlock all 3 pages and 3 million more documents.

Already have an account? Log in

Document Summary

Risk of breast cancer is thought to be influenced by events between age of menarche and age at first child birth. An international study was conducted to evaluate whether the risk of breast cancer differs for (cid:494)young(cid:495) versus (cid:494)old(cid:495) mothers. A srs of 3099 women who were <30 y old when they had their first child was identified; of these women, 1890 were hospitalized for breast cancer. A srs of 7546 women who were 30+ when they had their first child was identified. Of these women, 7038 were hospitalized for breast cancer. So this scenario deals with 2 samples: the sample of young mothers and the sample of older mothers. The data should be summarized with proportions bc breast cancer history is qualitative. We use an approx. z test for a difference in proportion. We look at null and alternate hypothesis: h0: p1=p2, the alternative hypothesis could be left tailed, right tailed or two tailed.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers

Related Documents