GG102 Final: Final Exam Note Lectures 1-19, Video 1

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turquoisemallard563

28 Dec 2011

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What is human geography: study of the spatial organization of human activity and of people"s relationship with their environments, where people live, what they do there, how people are connected, how they influence the world. Basic concepts for human geography: region, distance, scale. Absolute-> precise description e. g. latitude and longitude o o. What is a region: a larger-sized territory that encompasses many places, all or most of which share similar attributes in comparison with the attributes of places elsewhere (p. What is distance: absolute distance - measurement, relative distance - the friction of distance (degree of difficulty) The effects of distance on people"s behaviour can be charted. The o farther people have to travel, the less likely they are to do so. Patterns of spatial diffusion: expansion, relocation, hierarchical. The idea that there are multiple levels of interaction (local, regional, national, Processes at one scale can have significance at other scales.

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(a) An object is placed in front of a convex mirror. Draw a convex mirror (radius of curvature = 13 cm) to scale, and place an object 31 cm in front of it. Make the object height 4 cm. Using a ray diagram, locate the image and measure its height. (Do this diagram on paper. Your instructor may ask you to turn in this work.)Enter a number. 1 cm (image location, include sign)Enter a number. 2 cm (image height, include sign)(b) Now move the object closer to the mirror, so the object distance is 5 cm. Again, locate its image using a ray diagram.Enter a number. 3 cm (image location, include sign)Enter a number. 4 cm (image height, include sign)(c) As the object moves closer to the mirror, does the magnitude of the image distance become larger or smaller? 5stays the same smaller larger (d) As the object moves closer to the mirror, does the magnitude of the image height become larger or smaller? 6smaller larger stays the same (e) What is the ratio of the image height when the object distance is 5 cm to that when the object distance is 31 cm? Give your answer to one significant figure.h5 cm / h31 cm = Enter a number. 7

I NEED THIS ANSWERED BEFORE MIDNIGHT PST! I WILL RATELIFESAVER!

A very thin glass rod 4 meters long is rubbed all over with a silkcloth. It gains a uniformly distributed charge 1.6X10^â6 C. Twosmall spherical rubber balloons of radius 1.2 cm are rubbed allover with wool. They each gain a uniformly distributed charge of-8X10^â8 C. The balloons are near the midpoint of the glass rod,with their centers 3 cm from the rod. The balloons are 2 cm apart(4.4 cm between centers).

(a) Find the net electric field at the location marked by the X,0.6 cm to the right of the center of the left balloon. Things tothink about: Which objects make nonzero contributions to E field atthis location? What are the correct distances from sources to theobservation location? What is the direction of E field due to therod? (The drawing is not to scale; read the problem statementcarefully. Assume the +x axis is to the right, the +y axis is up,and the +z axis is out.)

E = ________ N/C

(b) What approximations did you make, if any? Which apply(1-4)?
1. Neglect polarization of balloons.
2. Use approximate formula for electric field of a chargedspherical shell.
3. Neglect polarization of rod.
4. Assume distance to observation location is small compared tolength of rod.

(c) Next a proton is placed at that same location (marked by thex). What is the force acting on the proton?

F = ________ N

Note: in parts (a) and (c) there should be an arrow over the"E" and the "F" but the custom equation function would not workproperly.

With this information I obtained: distance from laser to thewall was 126cm; when the light hit the wall we recorded 7dots x wasthe center and 2x2 was the distance of the dots on both sides ofthe center etc. (slit A width = .04mm with distance of the lightbeams on the wall respectively x=0mm 2x2=50mm 2x3=100mm 2x4=150mm)(slit B width =.04mm distance of the light beams on the wall x=0mm2x2=30mm 2x3=50mm 2x4=80mm) (slit c width=.08mm x=0mm 2x2=50mm2x3=100mm 2x4=150mm) (slit D width=.08mm x=0cm 2x2=40mm 2x3=50mm2x4=60mm)

1. Draw the interference pattern, labeling each of the maxima withtheir order number (calculation 1) and the angle (calculation 2)for each set of data.
2. Plot d*sin( ?), where d is the distance between the slits,versus the order number (calculations 1 and 2 below). Put the datafrom all your measurements on this graph.

Questions and Calculations
1. For each set of data, assign each bright spot an "order" bylabeling the central bright spot "zero" and counting outward inboth directions. Use only positive numbers.
2. Use your data for the location of each bright spot and thedistance from the slits to the wall to compute the angle betweenthe central maximum and other maxima, q. Compute sin(q) also.
3. From graph 2, find the wavelength of the laser light.

GG102 Final: Final Exam Note Lectures 1-19, Video 1

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