MA340 Study Guide - Cumulative Distribution Function, Normal Distribution, Binomial Distribution
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Ma340 quiz: july 9-10, 2013 solutions: an emergency center (open 24 hours per day) receives phone calls according to a poisson process with an average of 2 calls in any 20-minute period. 4 = 4. 5 and the probability that there are three or fewer (4. 5)ke 4. 5. The hourly rate is 6 per hour and 45 minutes accounts for 3 a 45-minute period is poisson with parameter 6 3 calls is. There are at least two ways to solve this problem. First, if t denotes the time (measured in hours after. 9:00 a. m. ) at which she receives her rst call then t has an exponential distribution with parameter 4. 5 and. P ( rst call betweeen 9 : 15 a. m. and 9 : 45 a. m. ) = p (0. 25 t 0. 75) (cid:90) 0. 75. Since these events are independent we have argue as follows. P ( rst call betweeen 9 : 15 a. m. and 9 : 45 a. m. ) = [e 4. 5(0. 25)][1 e 4. 5(0. 5)]
