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Mar 14 , 2013
This test has multiple choice: 22 Marks.
Fill in the blanks: 5 Marks
Pathway Question: 8 Marks
There are a total of 9 pages of this exam.
This includes 1 reference page with a table of
reduction potentials and the standard free energy
You are allowed to use a non-programmable
For multiple choice: Choose the BEST answer and
indicate your choice on the scantron. Please use a
pencil. Page 2 of 9
PART 1: Multiple Choice Questions (22 Marks)
1. What is the biochemical mechanism behind individuals who act as universal
a. They have a mutation in glycosyltransferase that prevents the addition of a
monosacchride to the O antigen on the surface of red blood cells.
b. They have functional glycosyltransferases that can add N-
acetylgalactosamine, and galactose to the O antigen on the surface of red
c. They have proteoglycans on the surface of their red blood cells.
d. Their blood does not induce Advanced Glycolsyation End Products when
it is transfused because the sugars on cell surface do not form aldehydes.
e. They have a mutation in hemoglobin which prevents the immune system
as detecting the red blood cells as foreign.
2. Which of the following molecules has the highest phosphoryl-transfer
a. Phosphoenolpyruvate (PEP)
b. Creatine phosphate
c. 1,3-bisphosphoglycerate (1,3-BPG)
e. Glycerol-3-phosphate (G3P)
3. What would be the net amount of ATP molecules produced by the following
reaction, assuming that oxidative phosphorylation is used to generate ATP?
ATP ADP NAD + NADH CH OH
CH 2H CH 2H 2
HO C H HO C H O C
Glycerol -2 Glycerol phosphate CH OPO -2
CH 2H kinase CH 2PO 3 dehydrogenase 2 3
glycerol glycerol phosphate dihydroxyacetone
4. A geneticist finds an isolated population in which many of the individuals
suffer from cataracts at an early age. These people likely….
a. Eat too many dairy products.
b. Have a mutation in one of the enzymes in galactose breakdown.
c. Have a mutation in one of the enzymes of glycolysis.
d. Have a mutation in the GLUT-1 transporter. Page 3 of 9
e. Have chronic activation of HIF-1 in their eyes.
5. What would be the physiological effect if someone was found to have a
dysfunctional GLUT4 glucose transporter?
a. They would have symptoms very similar to type I diabetes, since they
would not be able to release insulin in response to glucose.
b. They would suffer from heart disease due to increased glucose in the
blood leading to advanced glycosylation end (AGE) products and vascular
c. They would suffer from intestinal cramps and diarrhea because they would
be unable to take up fructose in the small intestine leading to an osmotic
d. They would be protected from cancer, because the transporter would be
unable to meet the metabolic needs of rapidly growing cells.
e. They would have symptoms similar to type II diabetes, since the
membrane localization of this transporter is regulated by insulin.
6. Beriberi symptoms are similar to which condition?
a. Type II diabetes
b. Mercury poisoning
d. MPTP poisoning
7. Which one of the following conditions will activate the pyruvate
dehydrogenase (PDH) complex?
a. High concentration of Acetyl CoA
b. High concentration of NADH
c. Phosphorylation of E1
d. High ATP/ADP ratio
e. High concentration of pyruvate
8. Which of the following conditions would DECREASE the rate of citric acid
a. High Pyruvate concentration
b. High Ca concentration
c. High FAD concentration
d. High NADH + H concentration
e. High ADP concentration
9. Pyruvate carboxylase c+rries out the following reaction: + -
a. Pyruvate + NAD +CoA+ → Acetyl-CoA + NADH+ H + HCO 3
b. Acetyl-CoA + ATP + HCO → Pyruv3te + ADP+ CoA
c. Oxaloacetate + ATP → Pyruvate + ADP +HCO 3-
d. Pyruvate + ATP +CoA → Acetyl-CoA + ADP + HCO 3
e. Pyruvate + ATP + HCO → Oxal3acetate +ADP Page 4 of 9
10. A botanist has discovered that the buds of a species of flower have an intense
citrus flavor, but act as a deadly poison when consumed by humans. Which
biochemical mechanism explains both the accumulation of citrate and the
a. Cyanide is concentrated in the plant leading to the shutdown of the
electron transport chain when it is consumed.
b. The plant produces a high concentration of succinyl-CoA which causes
negative feedback inhibition of the citric acid cycle when consumed.
c. Arsenite is concentrated in the plant leading to the inactivation of PDH,
and thus the citric acid cycle when it is consumed.
d. Fluoroacetate is produced by the plant causing the inhibition of aconitase,