# [PHYS 1010] - Midterm Exam Guide - Everything you need to know! (49 pages long)

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Published on 7 Feb 2017

Department

Physics and Astronomy

Course

PHYS 1010

Professor

York

PHYS 1010

MIDTERM EXAM

STUDY GUIDE

Lecture 20B January 9th 2017

Slide 20B2

Electric field(E)= force(F)/ charge (q) or K(constant(charge object 1(q1))

(charge object 2(q2))/r^2, make the q into a vector by r^ (r hat)

K=(8.99 x10^9 N/m^2 )q=(1.602x10^-19Coulomb)/r^2 (r^ radially

outward from proton)

If sketching we would draw an arrow pointing away from the point in

middle. The closer we get to the proton, the smaller r is so the electric

field is bigger ( sorter is weaker and longer is stronger)

What would a proton do? Use this to create the diagram.

Slide 20.B.3

Calculations: E=(k(-e)/re-^2)r^) + (k(+e)/re+^2 r^ )( we need two terms

because we are checking for both)

We can look up K number in textbook

Question( 0.00,0.00,0.00)

=-ke/1m^2 I^ (ihat) + ke/(1m)^2 -i^

=(-2ke/1m) I^

=-2(8.99 x 10^9 N/m^2/C^2)(1.602x10^-19C)/(1m^2)^2

=-2.88 x10^-9 N/c I^

Question (-1.11m,0.00,0.00)

=-ke/0.11m^2 -I^ (ihat) + ke/(2.11m)^2 -i^

= (1.19x10^-7 N/c i^)

Lecture 2

January 9, 2017

8:34 PM

Physics 1010 Lecture Page 1

find more resources at oneclass.com

find more resources at oneclass.com

= (1.19x10^-7 N/c i^)

The proton would move to the plus I^ direction ( toward -e) because it is

attracted to that and it would be longer since its really close to the field.

Question (0.00,1.00m,0.00)

= -ke/(sqroot(2m)^2(I^/2 +j^/2) + ke/(sqroot2m)^2 (-i^/sqroot2 +

j^/sqroot2)

=-k (8.99x 10^9) e(1.6 x 10^-19)/sqroot2 i^ N/c

=-1.02x10^-9N/C

Slide 20b.4

Physics 1010 Lecture Page 2

find more resources at oneclass.com

find more resources at oneclass.com

## Document Summary

Electric field(e)= force(f)/ charge (q) or k(constant(charge object 1(q1)) (charge object 2(q2))/r^2, make the q into a vector by r^ (r hat) K=(8. 99 x10^9 n/m^2 )q=(1. 602x10^-19coulomb)/r^2 (r^ radially outward from proton) If sketching we would draw an arrow pointing away from the point in middle. The closer we get to the proton, the smaller r is so the electric field is bigger ( sorter is weaker and longer is stronger) Calculations: e=(k(-e)/re-^2)r^) + (k(+e)/re+^2 r^ )( we need two terms because we are checking for both) We can look up k number in textbook. The proton would move to the plus i^ direction ( toward -e) because it is attracted to that and it would be longer since its really close to the field. = -ke/(sqroot(2m)^2(i^/2 +j^/2) + ke/(sqroot2m)^2 (-i^/sqroot2 + j^/sqroot2) =-k (8. 99x 10^9) e(1. 6 x 10^-19)/sqroot2 i^ n/c.