.pf{position:relative;background-color:#fff;overflow:hidden;margin:0;border:0}.pc{position:absolute;border:0;padding:0;margin:0;top:0;left:0;width:100%;height:100%;overflow:hidden;display:block;transform-origin:0 0;-ms-transform-origin:0 0;-webkit-transform-origin:0 0}.bi{position:absolute;border:0;margin:0}.c{position:absolute;border:0;padding:0;margin:0;overflow:hidden;display:block}.t{position:absolute;white-space:pre;font-size:1px;transform-origin:0 100%;-ms-transform-origin:0 100%;-webkit-transform-origin:0 100%;unicode-bidi:bidi-override;-moz-font-feature-settings:"liga" 0}.t:after{content:''}.t:before{content:'';display:inline-block}.pi{display:none}@media screen{.pf{margin:13px auto;box-shadow:1px 1px 3px 1px #333;border-collapse:separate}}.ff1{font-family:ff1;line-height:.992188;font-style:normal;font-weight:400;visibility:visible}.m0{transform:matrix(.236638,0,0,.320260,0,0);-ms-transform:matrix(.236638,0,0,.320260,0,0);-webkit-transform:matrix(.236638,0,0,.320260,0,0)}.m2{transform:matrix(.25834,0,0,.320260,0,0);-ms-transform:matrix(.25834,0,0,.320260,0,0);-webkit-transform:matrix(.25834,0,0,.320260,0,0)}.m1{transform:matrix(.314775,0,0,.320260,0,0);-ms-transform:matrix(.314775,0,0,.320260,0,0);-webkit-transform:matrix(.314775,0,0,.320260,0,0)}.m3{transform:matrix(.326217,0,0,.320260,0,0);-ms-transform:matrix(.326217,0,0,.320260,0,0);-webkit-transform:matrix(.326217,0,0,.320260,0,0)}.m4{transform:matrix(.680765,0,0,.320260,0,0);-ms-transform:matrix(.680765,0,0,.320260,0,0);-webkit-transform:matrix(.680765,0,0,.320260,0,0)}.ls0{letter-spacing:0}.ls1{letter-spacing:.017106px}.sc0{text-shadow:-.015em 0 transparent,0 .015em transparent,.015em 0 transparent,0 -.015em transparent}@media screen and (-webkit-min-device-pixel-ratio:0){.sc0{-webkit-text-stroke:.015em transparent;text-shadow:none}}.ws0{word-spacing:-92.200207px}.ws1{word-spacing:-84.628295px}.ws2{word-spacing:-74.793857px}.fc0{color:transparent}.fs4{font-size:49.582975px}.fs3{font-size:74.793857px}.fs2{font-size:84.628295px}.fs1{font-size:85.529541px}.fs0{font-size:92.200207px}.y0{bottom:0}.y5{bottom:388.209016px}.y6{bottom:391.635177px}.y2{bottom:418.161001px}.y4{bottom:422.843763px}.y3{bottom:423.819553px}.y1{bottom:507.293741px}.h7{height:38.78512px}.h6{height:58.505741px}.h5{height:66.1985px}.h4{height:66.903479px}.h3{height:72.121451px}.h2{height:507.295022px}.h1{height:1014.58492px}.h0{height:1014.588763px}.w1{width:783.997438px}.w0{width:784px}.x0{left:0}.x1{left:75.513651px}.x4{left:88.228916px}.x2{left:125.107081px}.x5{left:171.925089px}.x3{left:177.438747px}

MAT-1020 Final: Area and Volume Lecture 2

United States

College Algebra with Applications

Mathematics

Warren Colavito

Appalachian State University

Art from Prehistory to 1400

Page and Stage

<p>Area, Volume, and Surface Area In Exercises 75 and 76, find (a) the area of the region bounded by the ellipse, (b) the volume and surface area of the solid generated by revolving the region about its major axis (prolate spheroid), and (c) the volume and surface area of the solid generated by revolving the region about its minor axis (oblate spheroid).</p>
<p><picture><source srcset="https://s3.amazonaws.com/prealliance-textbook-qa.oneclass.com/qa_images/homework_help/question/qa_images/758136771186756/question/0.webp?img=c04c7cfe809d6bd9702a2652bdcf798e" type="image/webp"><img src="https://s3.amazonaws.com/prealliance-textbook-qa.oneclass.com/qa_images/homework_help/question/qa_images/758136771186756/question/0.png?img=cc0d0e7ad97611acfae244834989186a" data-mlang="latex" data-equation="%5Cfrac%7Bx%5E%7B2%7D%7D%7B4%7D%2B%5Cfrac%7By%5E%7B2%7D%7D%7B1%7D%3D1"></picture></p>

<p>Volume and Surface Area</p>
<p>Show that a rectangular box of given volume and minimum surface area is a cube.</p>

<div style="font-family:'Helvetica Neue', Helvetica, Arial;color:#333333;"> <div> <br> <picture><source srcset="https://prealliance-textbook-qa.oneclass.com/qa_images/homework_help/question/qa_images/73/7310883.jpeg" type="image/webp"></source><img src="https://prealliance-textbook-qa.oneclass.com/qa_images/homework_help/question/qa_images/73/7310883.jpeg" alt=""></picture> </div> </div> <div id="d97" class="hidden">Problem 11 (t point The srtace area of a right-circular cone of radius r and height h is S = ÏrVr4h2, and its volume is V-rr2h. a) Determine h and r for the cone with given surface area S = 6 and maximal volume V. S? (b) What is the ratio h/r for a cone with given volume V = 7 and minimal surface area (c) Does a cone with given volume V and maximal surface area exist? A. yes B. no </div>

MAT-1020 Final: Area and Volume Lecture 2

Get access

Related Documents

MAT-1020 Lecture 10: Area and Volume Lecture 1

MAT-1020 Lecture 33: Inverse Proportionality

MAT-1020 Lecture 31: Varying Jointly and Odd and Even Powers

Related Questions