CHEM-C 101 Study Guide - Midterm Guide: Squared Deviations From The Mean, Standard Deviation, Interquartile Range
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CHEM-C 101 Full Course Notes
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S320/s520: to nd the average number of cars owned per household in the u. s. , a random survey of n = 100 american households is taken. The results are given in the table below. 100 (a) calculate the sample mean and standard deviation. To nd the standard deviation, we calculate the sum of the squared deviations: The sample standard deviation is then(cid:112)111. 71/99 = 1. 06. (b) calculate the sample median and interquartile range. The 50th and 51st highest values are both 2, so that"s the sample median. The 1st quartile is 1 and the 3rd quartile is 2 (c) find an approximate 95% con dence interval for the mean number of cars owned per household in the u. s. Such an interval is 1. 77 1. 96 1. 06. 100, or 1. 56 to 1. 98 cars per household: we wish to test if the center of a population is zero. We observe a random sample of size 15: