Purcell 6.18 Two long coaxial aluminum cylinders are charged to apotential difference of
50 statvolts. The inner cylinder has an outer diameter of 6 cm, theouter cylinder an inner
diameter of 8 cm. With the outer cylinder stationary the innercylinder is rotated around its axis
at a constant frequency of 30 Hz. Describe the magnetic field thisproduces and determine its
intensity in gauss. What if both cylinders are rotated in the samedirection at 30 Hz?
I know this is virtually the same as a solenoid with currentrunning....
B=(4pi/c)I*n (I= current, n= the number of turns)
I thought once i find Q, i can divide it by 2pi*a(the circumferenceof the inner cylinder) and then multiply it by omega*a to find thetotal amount of current going through a strip on the surface of thecylinder to find the total flux of charges ...
However, the answer i found says (Q/L)* omega is what is comparableto I*n ...
Im like what the fuck...