MATH 151 Midterm: MATH 151 TAMU Y2010 2010c Exam 1a Solutions
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Solutions-form a: c: find the vector ~a that has magnitude |~a| = 12 and makes an angle of 300 with the positive x-axis. Since 300 = 360 60 , our reference angle is 60 in quadrant iv. ~a = h12 cos 60 , 12 sin 60 i = d6, 6 3e. 6t2 + 3t lim t : e: (3 t)(2t + 4) = lim t : a: find all vertical asymptotes for f (x) = First by simplifying f (x), we nd that x2 1 x3 + x2 . (x + 1)(x 1) x2(x + 1) f (x) = , provided x 6= 1 and x 6= 0. Thus the only vertical asymptote occurs at x = 0. x 1 x2: b: a force ~f = 2~i + 6~j moves an object from the point p (1, 3) to the point q(3, 7). W = ~f ~d = h2, 6i h2, 4i = 28 foot pounds.
