MATH 152 Midterm: MATH 152 TAMU 2010a Exam 1a Solutions

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31 Jan 2019
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The average value of f (x) = interval [0, 2] is de ned as x (x + 1)2 on the (x + 1)2 dx. 2(cid:18)ln u + fave = du = dx, and x = u 1. fave = (x + 1)2 dx = u2(cid:19) du u(cid:19)(cid:12)(cid:12)(cid:12)(cid:12) 0: d. since the cable is 80 feet long and weighs 240 pounds, it weighs 3 pounds per foot. When we pull the rst 10 feet to the top, we need to remember we are also pulling the bottom 70 feet of the cable up. Revolve the region bounded by y = x x2, the x-axis, x = 0 and x = 1 about the y-axis: We will use the method of cylindrical shells: Since the graph of y = cos x is above the graph of y = 1, 0 = 1 + x cos(cid:18) x (cos x ( 1)) dx.

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