PHYS 2401 Midterm: PHYS 2401 TTU 2401 Exam4 sol2
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[section 1. 4, problem 4] a rocket is shot straight up. During the initial stages of ight is has acceleration 7t m/s2. The engine cuts out at t = 10 seconds. How high will the rocket go? (neglect air resistance. ) There are two phases of the ight, powered and unpowered. Let r be the distance of the rocket from the center of the earth. Then the velocity is v = dr/dt and the acceleration is dv/dt. During the powered phase of the ight, we are given that the acceleration is. 7t m/s2 (where t = 0 is the time the rocket is red), so. Integrating both sides of this equation gives dv dt. Setting t = 0 is this equation shows that c is the velocity at t = 0. This is zero, since the rocket is not moving before we start the engine.
