MATH 404 Midterm: MATH404_HERB-R_SPRING2005_0101_MID_SOL

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10 Jan 2019
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Math 404 - exam 2 - solutions: l k is a sub eld of gf (pn) so that l k has order pa for some integer a 0. I claim that a = d = gcd(s, t) is the greatest common divisor of s and t. first, since l k l, we know by theorem. Since d|t k has a sub eld k1 of order pd. But both l1 and k1 are sub elds of gf (pn) and gf (pn) has a unique sub eld of order pd by theorem 22. 3. Then k0 = e, k1 = q(i), k2 = q( 3), k3 = Then k0 = e, k1 = q(51/3), k2 = q(51/3 ), k3 = Let a, b g. then (an )(bn ) = (ab)n = (ba)n = (bn )(an ) just in case ab(ba) 1 = aba 1b 1 n .

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