MATH 2B Midterm: MATH2B, Chapter 6.1 term test 2

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15 Sep 2018
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MATH 2B Full Course Notes
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The volume created by the area rotated around the x-axis looks like a cone. You can use integrals to find the volume of the cone. The x and y intercepts are where the function intercepts with the other. Here, you can move outside the integral and foil out (2 12)2. = (4 2 + 1123) ( 0 4) = (16 16 +6412) (0 0 + 0) Now you can check whether this is true using the actual formula for volume of a cone. Find the volume between the curves = and = 2 rotated around the . The unique thing about this function is that when rotated around the x-axis, there is an open space in the middle. Compile the volume after finding the boundaries and radii. Set equations equal to each other to find boundaries. = (133 155) ( 0 1)

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