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Practice Quiz 1A Answer Key.doc

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Department
Chemistry
Course
CHM 2046
Professor
Christou
Semester
Spring

Description
1 NAME:                               CHM 2046      Quiz 1A        Spring, 2006 Be careful to give your final answer to the correct significant figures. SEE THE END FOR USEFUL  INFORMATION. Show your work. 1. a) (2 points each) Balance the following reactions and write down their      mass­action expression, Q . c 3 [N H2 [ ]2 2 2 NH (3  ⇌  N (g)2   3 H (g) 2           cQ  =    [NH 3 ] 2                                                                                                    [H 2   ][ N 2 4 ] 2 H O  (g) +  2 NO (g) ⇌ 2 H O (g) +  N O  (g)   Q =      2 2 2 2 2 2 4 c [H O ][ NO ] 2 2 b) (5 points) At a particular temperature, K  = p79 for the reaction 2 SO  2g) + O  2g) ⇌ 2 SO  (g3  In a particular reaction carried out, the pressures of the gases at a  particular time are 0.12 atm  (atmospheres) of SO , 2.2 atm of O , a2d  2.4  atm of SO . 3as the reaction reached equilibrium yet?  Explain. p(SO ) 2 (2.4) 2 Q p=  3  =   = 333        ∴ Q  ≠pK   ∴pnot  at equilibriu m p(SO ) p2O ) 2 (0.12) 2 (1.2) If not, in which direction is it proceeding? Explain. Q p> K  p∴ reaction proceeding to the left. c)  (4 points) N2O 4(g) was introduced into a 2.00 L flask and allowed to  reach equilibrium at 100  ºC.  At equilibrium, the flask contained 0.38 mol N 2  4g) ⇌ 2 NO  (g)2 of N O and 0.40 mol of NO . What is K  for this reaction at 100 ºC?  2 4  2 c [NO ] 2 (0.20) 2 K  =  2 = = 0.21 c [N O2] 4 0.19 2. (6 points total)  a) At 350 K, the reaction below has K  = 1c05. What is K  at 350pK? 2 CH C2  2g) ⇌ CH  (g4 + CCl  (g)4    K p= K c K p=  1.05  b) At 300 K, the reaction below has K = 27c.  What is K  at 300 p? 2 SO  2g) + O  2g) ⇌ 2 SO  (g3    Δn = ­1  therefore K p=  11.3 Kc 279 Kp = = = 11.3 RT (0.082)(30 0) 3. (3 points each) The reaction below has K  = 1c. What are the K  valuescfor the equilibria in a) and b)?   Explain how you got your answer. CO(g) + H O(2) ⇌ CO (g) +2H (g) 2 a)  2CO(g) + 2H O(g) ⇌ 2CO (g) + 2H (g) 2 2 2 K c  144 2 K’c= K c b)  CO (2) + H (g2 ⇌ CO(g) + H O(g) 2 K c  0.083   2 HI       ⇌   H 2 +  I 2 K’c= 1/K   c   I     0.150 M     
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