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Final

# PHYSICS 140 Study Guide - Final Guide: Sound Intensity, Switch, Scantron CorporationExam

by OC2703135

Department

PhysicsCourse Code

PHYSICS 140Professor

Timothy McKayStudy Guide

FinalThis

**preview**shows pages 1-3. to view the full**15 pages of the document.**Physics 140, Winter 2013

FINAL EXAM

April 26, 2013

Physics Department, University of Michigan

FORM 1

Please print your name:

____________________________________________

Your DISCUSSION SECTION or INSTRUCTOR:_________________________

INSTRUCTIONS AND INFORMATION

1. Fill in YOUR NAME, SECTION NUMBER and EXAM FORM NUMBER on the scantron.

2. RECORD YOUR ANSWERS ON THE SCANTRON USING A #2 PENCIL.

This is a 120-minute, closed book exam. You may use four 3” x 5” cards on which

you have your favorite equations. You also may use a calculator but please do not

share calculators.

3. There are altogether 25 multiple choice questions. All questions are of equal value.

Equations that you may find useful:

s

f

= s

i

+ v

0

t + ½ a t

2

θ

f

= θ

in

+ ωt + ½ α t

2

Rod, axis through one end I =1/3ML

2

v

f

= v

0

+ at ω

f

= ω

0

+ α t Rod, axis through center: I = 1/12ML

2

a

rad

= v

2

/r = rω

2

v

t

= r ω, a

t

= r α Solid sphere: I = 2/5 MR

2

F = ma = dp/dt τ = r × F = dL/dt=Iα

αα

α Hollow sphere: I = 2/3 MR

2

p = mv L = r ×

××

× p = Iω Solid cylinder: I = ½ MR

2

W = F.s F

k

= µ

k

N Hollow cylinder I = ½M(R

12

+R

22

)

F

x

= −dU(x)/dx U

spring

= ½ kx

2

Hoop: I = MR

2

F =GM

1

M

2

/r

2

G = 6.67×10

-11

Nm

2

/kg

2

U = –GM

1

M

2

/r v

orb

= (GM/r)

1/2

W = ∆K I = I

cm

+ Md

2

v

esc

= (2GM/R)

1/2

R

E

= 6.38×10

6

m

∆K + ∆U = W

n.c.

K

rot

= ½ Iω

2

M

E

= 5.97×10

24

kg

in,2

21

2

in,1

21

21

f,1

v

mm

m2

v

mm

mm

v+

+

+

−

=

x(t) = A cos (ωt + φ) a

x

(t) = –ω

2

x

in.2

21

12

in,1

21

1

f,2

v

mm

mm

v

mm

m2

v+

−

+

+

=

ω=(k/m)

1/2

Simple pendulum: ω = (g/L)

1/2

Physical pendulum: ω = (mgd/I

pivot

)

1/2

Young’s modulus Y = (F

⊥

L

0

)/(A∆L) ρ

water

= 1000 kg/m

3

ρ

air

= 1.2 kg/m

3

p = p

o

+ ρgh p + ρgh + ρv

2

/2 = const.

1 atm = 1.013×10

5

Pa = 1.013 bar = 14.7 lb/in

2

1 mm Hg = 1 torr = 133.3 Pa

y(x,t) = Acos(kx -ωt) k = 2π/λ ω = 2πf = 2π/T v = (F/µ)

1/2

P(x,t) = µvω

2

A

2

sin

2

(kx - ωt) Beat frequency f

b

= f

1

-f

2

P

aver

= µvω

2

A

2

/2 f

L

= (v ± v

L

)/(v

v

S

) f

S

Sound intensity level in dB: β=10 log

10

(I/I

0

) Volume of sphere V = (4/3)πR

3

Only pages 1-3 are available for preview. Some parts have been intentionally blurred.

Only pages 1-3 are available for preview. Some parts have been intentionally blurred.

Physics 140, Winter 2013, Final Exam

Problem 1:

Two blocks, with masses 10 kg and 5 kg, are connected by light strings and attached to

the ceiling of an elevator as shown in figure. The elevator accelerates upward with 4

m/s

2

. What is the tension in the string attached to the ceiling of the elevator?

A. 69 N

B. 118 N

C. 138 N

D. 187 N

E. 207 N

Problem 2:

Which equation describes a plane wave travelling in the direction opposite to the x axis?

A. cos +

B. cos +

C. coscos

D. cos −

E. cos +

4 m/s

2

T ?

10 kg

5 kg

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