# PHYSICS 140 Study Guide - Final Guide: Sound Intensity, Switch, Femtolitre

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Published on 29 Apr 2019
School
U of M
Department
Physics
Course
PHYSICS 140
Professor
Physics
140,
FaIl
2012
FINAL
EXAM
December
14,
2012
Physics
Department,
University
of
Michigan
FORM
1
print
your
name:
_________________________________________
Your
DISCUSSION SECTION
or
INSTRUCTOR:__50
L
UI
&
3
INSTRUCTIONS
AND
INFORMATION
1.
Fill
in
SECTION
NUMBER
and
EXAM
FORM
NUMBER
on
the scantron.
2.
RECORD
YOUR
ON
THE
SCANTRON
USING
A
#2
PENCIL.
This
is
a
120-minute,
closed
book
exam.
You
may
use
four
3”
x
5”
cards
on
which
you
have your
favorite
equations.
You also
may
use
a
calculator
but
do
not
share
calculators.
3.
There
are
altogether
25
multiple choice questions.
All
questions
are
of
equal
value.
Equations
that
you
may
find
useful:
sf=s+vOt+½at
0f=0
0
+wt+½at
2
vf=v
0
+at
o)f=00+at
v1
=ro),
arcz
F
=
ma
=
dp/dt
=
r
x
F
=
dL/dt=Ic
p=mv
L=rxp=ki)
W=F.s
W=t(0
2
—0
1
)
F=-VU
Fk=?IkN
=
mv
2
/r
Uspring
=
½
kx
2
W=AK
I=Icm+Md
2
AK+AUW
0
Krot=½Iff
2
Rod,
axis
through
one end
I
=l/3ML
2
Rod,
axis
through
center:
I
=
l/12ML
2
Solid
sphere:
I
=
2/5
MR
2
Hollow
sphere:
I
2/3
MR
2
Solid cylinder:
I
=
½
MR
2
Hollow cylinder
I
=
½M(R
12
+R
22
)
Hoop:
1=
MR
2
F
=GM
1
M
2
/r
2
U=—GM
1
M
2
/r
=
(2GM[R)”
2
m
1
in-,
2m-,
V]f
=
-
v1
+
-
ME
=
5.97x10
24kg
in
1
+
1fl
2
Jfl
+
1fl
2
G
6.67x10”
Nm
2
/kg
2
vorb
=
(GM/r)”
2
RE
=
6.38x10
6
m
2ni
1
in,
—m
1
=
v1
+
v2,,
x(t)
=
A
cos
(ot
+
(p)
a(t)
=
—o
2x
w=(k/m)”
2
+
in
2
m
1
+
in
2
Simple pendulum:
w
=
(gIL)”
2
Young’s
modulus
Y
=
(F
1
L
0
)/(AAL)
p
=
p0
+
pgh
1
atm=
1.Ol3xlO
5
Pa=
l.Ol3bar=
14.7
lb/in
2
y(x,t)
=
Acos(kx
-0t)
k
=
2m/
P(x,t)
=
jivw
2
A
2
sin
2
(kx
-
(Ut)
Paver
=
ivoiA
/2
Sound
intensity
level
in dB:
3=l0
log
1
o(TIIo)
Physical
pendulum:
o
=
(mgd/I
0
)”
2
Pwater
=
1000
kg/rn
3
p
=
1.2
kg/rn
3
p
+
pgh
+
pv
2
/2
=
const.
1
mm
Hg
=
1
torr
=
133.3
Pa
I
I’
w=2tf=2it/T
v=(FIi)
-
Beat
frequency
fb
=
fi-f
2
fL
=
(v
±
vL)/(v
vs)
fs
Volume
of
sphere
V
=
(413)mR’
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Table
9.2
Moments
of
Inertia
of
Various
Bodies
(a)
Slender
rod,
ax
is
th
mugh
center
(b)
Sleiider
rod.
axis
tl1lOLii1h
out
end
/
!
i
2
(c)
l?cci.angulur
plate.
ax
s
through
co2nler
/
=
+
,,2)
(d)
Thin
rectangular
plate,
axis
along
edge
I
Mu
(i
(e)
Hollow
cylinder
(g)
Thin—walled
hollow
cylinder
I
=
MI?
2
(h)
Solid
sphere
(I)
Thin—or
al
led
hollow
sphere
I
=
MR
2
/
=
Mt
2
(0
Solid
c
under
I
=
M(R
2
±
R)
/
=
MR
2
42
‘2
/
MR
2
[-J?H
1;
2012
Powson
Edca:Dn,
Inc
.4
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Physics
140,
Fall
2012,
Final
Exam
Problem
1:
Three
identical
spring scales
are
attached along
a
straight
line
as
shown.
The
scale
on
the left
is
attached
to
a
wall.
A
force
of
15
N
is
applied
to
the
scale
at
the
right.
What
is
the
on
the
middle
scale?
is
T
i
T
15M
HIiiIIiIiiI..fIIjHhIIIHI_IHIIIIIIlHI
15N
C.45N
D.ION
E.5N
Problem
2:
A
person
is
standing
at
the
left
end
of
a
12-feet canoe.
The
canoe
is
twice
as
heavy
as
the person
is,
and
the
canoe
is
completely
symmetric
with
respect
to
its
center.
Where
is
the
center
of
mass
of
the
“person
+
canoe” system?
A.
2
feet
from the
person
B.
3
feet from
the
person
4
feet
from
the
person
D.
6
feet
from
the
person
E.
8
feet from
the
person
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7/Z
i(o)
-t-
M
C
‘7-kl-t-M
-
2i()
4
t
ttte
J
t4e
rç1kl
0
A.ON
®15N
Tke
S+r’ij
)L’
1
-t
tt
(&c.cc.&s)
sc
9
J
c
‘c
i
Tkerfr)
k
ec1
Lo
t
w
-&kci
L
0
-ike.
C2?’4
w.oS
‘M
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## Document Summary

Your discussion section or instructor:__50 l ui & 3. Fill in your name, section number and exam form number on the scantron: record your answers on the scantron using a #2 pencil. You may use four 3 x 5 cards on which you have your favorite equations. You also may use a calculator but please do not share calculators. Equations that you may find useful: sf=s+vot+ at 0f=00+wt+ at2 vf=v0+at o)f=00+at. = r x f = dl/dt=ic arad=v/r=:ro) v1=ro), arcz. Jfl + 1fl2 in, m1 m1 + in2 v2,, Me = 5. 97x1024kg x(t) = a cos (ot + (p) a(t) = o2x w=(k/m) 2. Young"s modulus y = (f1l0)/(aal) p = p0 + pgh. 1 atm= 1. ol3xlo5pa= l. ol3bar= 14. 7 lb/in2 y(x,t) = acos(kx -0t) Sound intensity level in db: 3=l0 log1o(tiio) k = 2m/ Pwater = 1000 kg/rn3 p = 1. 2 kg/rn3 p + pgh + pv2/2 = const. 1 mm hg = 1 torr = 133. 3 pa w=2tf=2it/t.