# PHYSICS 140 Study Guide - Final Guide: Notecards, Scantron Corporation, Axa

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Published on 29 Apr 2019

Department

Physics

Course

PHYSICS 140

Professor

Physics

140,

Fall

2013

Final Exam

December

13,

2013

Form

1

50L

(JTIOI\J5

Your

name:

________________________________________________

Last First

Your

UMID

number:

A4

J/C

c-ic,

1K

Fill

in

your

name,

student

ID

number,

and

form

number

on

the

scantron

and

in

the

spaces

above.

All

cell

phones,

text

massaging

devices, computers,

and

communication

devices

of

any

type

must

be

turned

off

and

stowed

out

of

site.

The exam

is

closed

book.

You may

use

four

3”x5”

(7.5

cm

x

12.5

cm)

notecards

(both sides). You

may

also

use

a

calculator

that

cannot

communicate

with

the

outside

world.

You

cannot

share

calculators, notecards,

scratch paper,

exam

booklets,

or

scantrons.

Exam responses

must

be

based

on your

individual

work

only.

You

must

mark

the

correct answer

on

the

scantron

to

get

credit

for

each

problem.

The

exam

is

125

minutes

long.

There

are

26

multiple-choice

questions.

All

questions

are

of

equal

value.

There

is

no

penalty

for guessing.

At

the

end

of

the

exam,

hand

in

your

scantron

and

show

your

UM

ID.

Constants

and

equations

you

may

find

useful:

7

x

=

xo

+

v0

t

+

arI2

=

1

”Ox

+

cit

7

=

i’

+

2a(x

—

xO)

0

00

+

c0

0

-t

+

at2/2

(0

=

(0o

+

Ctt

77

=

030:

+

2u-(0

—

0)

v

=

Rm

dv/dt

=

Ra

7

7

1

ra1

=

i1/R

=

(0

R

VA/Q

=

VA/B

+

V

81

ç

(continued

on

the

next

page)

Tab’e

9.2

Moments

of

Inertia

of

Various

Bodies

(a)

Slender

rod,

axis

through

center

(b)

Slender

rod,

axis

tlirouh

one

end

1=

(c)

Rectangular

plate,

axis

through

center

I

=

M(n

+

62)

(d)

‘fh

in

rectangu

ar

plate,

axis

along

edge

I

=

(e)

Ilollow

CYlinLler

I

=

+

le,)

/

N

I’

4\

N

I

(continued from

the

previous

page)

I

m

1

r

12

+

m2r2

+

I

=

‘CM

+

Md

2

Fb

=

PfluidVdisplacedg

F,

5

=pkN

F

=

Gm

Jm2Ir

Vorb

=

(GIVI/r)”

2

vesc

=

(2GM/r)

1

’

2

W=

p

=

iiiv

f

1=

=

j

Pdt=avert

rCM

=

(nz,r,

+

1n2r2

+

)/(in

+

1n2

F

5

=

—

dPE/dx

2

I

I\E

=

tnv

/2

t=rxF

L

=

r

x

p

=

10)

Pd

=

P0+

pgd

A,v,

—A

2v2

p’

+pgy

+

½pv,

2

=P2

+pgy2

+

½pV2

2

x(t)

=

Acos(cot

+

qt)

=

—

cox

co

(Wm)’

2

or

(g/L)”

2

or

(mgd/Ipjvot)U

2

co=2irf=2n/T

k

=

2nL.

=

co/k

=

ET=

}f=

(F/p)”

2

g=9.8m1s

2

G=

6.67

x

10”

Nm

2

/kg

2

REartli

=

6.38

X

106

rn

MEarth

=

5.97

X

1024

kg

Patm

1

atm=

1.013

x

i0

5

Pa

Pwater

=

1000

kg/rn

3

J=•

MR

2

(1)

Solid

cylinder

(g)

Thinwalled

hollow

(h)

Solid

sphere

cylinder

=

MR

2

I

=

(i)

Thinwalled

hollow

sphere

MI?

2

—-

<‘

11

\/“\

\

Hi

1?

RKE

=

1c02/2

GPE

=

—

Gm,in

2

/r

EPE

kv

2

/2

TKE

±

RKE

1

+

GPEI

+

EPE

1

+

W

00

=

TKEf

+

RKEf

+

GPEf

+

EFEf

1.

Find(IXj)k.

h)

I

c)

0

d)

j

e)

—1

_

k

A