BIO 325 Study Guide - Fall 2018, Comprehensive Midterm Notes - Dna, Protein, Genome

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BIO 325
MIDTERM EXAM
STUDY GUIDE
Fall 2018
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Gene Expression
A gene’s nucleotide sequence is co-linear with the amino acid sequence
Yanofsky how do mutations in DNA correspond to mutations in protein
Mutagenized E. coli
Grew on media that contains tryptophan
Replica plated to find colonies that don’t grow without tryptophan
Isolated trpA auxotrophs point mutants
Mapped sites of mutations in DNA by recombination
Purified mutant trpA proteins and determined amino acid sequences
o A gene’s nucleotide sequence is co-linear with the amino acid sequence of the
encoded polypeptide
The positions of mutations in DNA nucleotides corresponded with the
positions of the amino acid substitutions
o Each nucleotide is part of only a single codon (non-overlapping codons)
Each point mutation only altered one amino acid
o A codon is composed of more than one nucleotide
Different point mutations may differ the same amino acid
Crick & Brenner’s experiment with phage rIIB gene
Proflavin inserts or deletes a single base pair
A gene has a reading frame
o Reversion occurred when a first proflavin-induced mutant was exposed to
proflavin for the second time (+1 and -1)
A codon is a triplet
o Gene can still function with three or multiples of three changes
Wild-type phenotype may result when the reading frame is restored through frameshift
mutations, which are insertions or deletions that shift the reading frame.
Transcription
New phosphodiester bond forms at the 3’ end (like in DNA replication)
RNA is also made in 5’ 3’ direction
Translation
mRNA is read in 5’ 3’ direction
Only one DNA strand is transcribed for a gene, but either top or bottom strand is used to
transcribe different genes
RNA-like strand = sense strand = coding strand
Template strand = antisense strand = noncoding strand
The genetic code is universal
- In vitro translation with synthetic mRNAs reveal the first codon identities
- Polymononucleotides
- Polytrinucleotides
- Polytetranucleotides
- Deduced codons from amino acid sequence
- Some ambiguities
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Ribosome binding experiments with synthetic mini-mRNA identified remaining codons
The genetic code is degenerate and unambiguous
Unambiguous a certain codon always codes for the same amino acid
Degenerate (reduntant) several codons can code for the same amino acid
The opening frame in DNA is defined by the start codon (ATG)
Central concepts in gene expression
Transcription (DNA to RNA)
o Initiation, elongation, termination
o Initiation in prokaryotes vs. eukaryotes
RNA processing in eukaryotes
o 5’ cap
o splicing
o poly-A tail
Translation (RNA to protein)
o Initiation, elongation, termination
o Initiation in prokaryotes vs. eukaryotes
o tRNAs, wobble and redundancy
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Document Summary

A gene"s nucleotide sequence is co-linear with the amino acid sequence. Yanofsky how do mutations in dna correspond to mutations in protein. Gene expression: mutagenized e. coli, grew on media that contains tryptophan, replica plated to find colonies that don"t grow without tryptophan, mapped sites of mutations in dna by recombination, purified mutant trpa proteins and determined amino acid sequences. Wild-type phenotype may result when the reading frame is restored through frameshift mutations, which are insertions or deletions that shift the reading frame. Transcription: new phosphodiester bond forms at the 3" end (like in dna replication, rna is also made in 5" 3" direction. Translation: mrna is read in 5" 3" direction. Only one dna strand is transcribed for a gene, but either top or bottom strand is used to transcribe different genes: rna-like strand = sense strand = coding strand, template strand = antisense strand = noncoding strand. In vitro translation with synthetic mrnas reveal the first codon identities.

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