BIOL 204 Chapter Notes - Chapter 2: Mendelian Inheritance, Zygosity, Germination

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silverwhale409

11 Apr 2018

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Investigating the expression of a recessive gene found in albino corn. The hypothesis for this experiment stated that breeding heterozygous albino corn seeds would yield an equal amount of both homozygous and heterozygous phenotypes and genotypes. I predict that if the parent carries the recessive albino then about of the offspring will show the albino phenotype. Mendelian genetics or inheritance refers to the fact that certain traits or features in living things manifest in their offspring without any observable similarities in their parents (russel. These traits are transmitted through genes from parent to offspring depending on whether they are dominant or recessive in nature. Dominant genes are expressed regardless they are homozygous or heterozygous, but the manifestation of recessive genes only takes place if their expression is homozygous (russel 239). This experiment was carried to investigate the expression of a recessive gene found in albino corn in the first generation after germination in laboratory setting.

Related Questions

1. A person is described as a carrier for a particular genetic disease. What does this tell you about their genotype?

2. For any given gene, the principle of independent segregation predicts that each gamete produced as a result of meiosis will contain ____________________

3. A pair of alleles is said to be heterozygous when:

4. In a diploid species, cells can have up to ___ alleles of a particular gene.

5. In a cross between a homozygous dominant parent and a homozygous recessive parent, the number of phenotypic classes observed in the offspring is ______

6. For a person of genotype Xx, the genotype of their gametes may be ______________

7. In a "test cross", an individual of unknown genotype is crossed with a ___ individual to determine the unknown genotype.

8. An albino woman has a child with a phenotypically normal man with no family history of albinism (which is a rare recessive disorder). What percentage of their children are likely to be albino?

9. An individual with the dominant phenotype, but an unknown genotype, is test-crossed, and all of the offspring exhibit the dominant phenotype. The genotype of the unknown individual is ______________

10. If two heterozygous individuals for a recessive disease (carriers) have a child, what is the chance that their child will develop the disease?

11. In a monohybrid cross between two true-breeding parents that both exhibit the dominant phenotype, ___ percent of the offspring will exhibit the recessive phenotype.

12. In a particular type of tomato plant, red fruit is dominant over yellow fruit, and dwarf height is a recessive trait. If two heterozygous plants were crossed, what proportion of the offspring would show the dominant phenotype?

13. In a cross between a BbRr individual and a BBRR one, what do the following represent: BR, Br, bR, br?

14. In humans, the gene that determines whether an embryo develops as a male or a female is carried on _____________

amaranthhare726

7. When a pea plant of genotype Aa Bb produces gametes whatproportion will be ab?

8. Hamsters are long haired if they have the genotype LL or Ll andthey are short haired if they have the genotype ll. A long hairedhamster is mated with a short haired hamster. Half of the offspringare long haired and half are short haired. This allows us toconclude that the long haired parent hamster is? D

9. In peas yellow seed (Y) is dominant over green seeds (y) andtall plant (T) is dominant over short plant (t) .Calculate theprobability of the genotypes and phenotypes. in the F2 generationof a dihybrid cross that begins when a dominant homozygote iscrossed with a recessive homozygote. You must show the all of theprobability calculations. D

10. In a fruit fly experiment, two gray-bodied fruit flies producemostly gray-bodied offspring, but some of the offspring have blackbodies. If there are 280 offspring, how many will you predict willhave grey bodies and how many will have black bodies? How many ofthe 280 offspring do you predict will be heterozygous? Show yourwork. D

11. In a dihybrid cross AaBb X AaBb what fraction of the offspringwould be D

i) homozygous for both recessive traits
ii) heterozygous for both traits
ii) homozygous for both traits

amaranthwasp103

Question 1

What would be the dimensions of a Punnett square for the cross Hh x hh?

		4 x 4
		2 x 2
		2 x 1
		1 x 1

Question 2

In dogs, the gene for fur color has two alleles. The dominant allele (G) codes for grey and the recessive allele (g) codes for black fur. The female dog is heterozygous. The male dog is homozygous recessive. Figure out the phenotypes and genotypes possible in their puppies by using a Punnett Square. (provide answers on one line with commas between - xx, xx, xx, xx)

Genotypes: , ,

Phenotypes: ,

Question 3

The fundamental Mendelian process which involves the separation of alleles located at the same spot on the chromosome would be called ___.

		segregation
		independent assortment
		continuous variation
		discontinuous variation

Question 4

Using the information given on dominant and recessive traits, state the phenotype for each genotype. Purple flowers are dominant to white flowers in pea plants.

-A.B.C.	PP_____________
-A.B.C.	Pp____________
-A.B.C.	pp_______________

A.	purple flowers
B.	purple flowers
C.	white flowers

Question 5

In dogs, the gene for fur color has two alleles. The dominant allele (G) codes for grey and the recessive allele (g) codes for black fur. The female dog has black fur and the male dog is homozygous dominant. Make a Punnett square to determine the chance of getting each genotype and phenotype below.

-A.B.	Probability of GG:
-A.B.	Probability of Gg:
-A.B.	Probability of gg:
-A.B.	Probability of gray fur:
-A.B.	Probability of black fur:

A.	100
B.	0

Question 6

Using the information given on dominant and recessive traits, state the phenotype for each genotype. Round seeds are dominant to wrinkled seeds in pea plants.

-A.B.C.	RR______________
-A.B.C.	Rr _____________
-A.B.C.	rr ____________

A.	round seeds
B.	wrinkled seeds
C.	round seeds

Question 7

Using the information given on dominant and recessive traits, state the phenotype for each genotype. Hairy knuckles are dominant to non-hairy knuckles in humans.

-A.B.C.	HH_____________
-A.B.C.	Hh ___________
-A.B.C.	hh _________________

A.	non-hairy knuckles
B.	hairy knuckles
C.	hairy knuckles

Question 8

An allele is ___.

		one of the bases in DNA
		an alternate form of a gene
		another term for epistasis
		present only in males and is responsible for sex determination

Question 9

In a cross of a round hybrid pea with a true breeding round parent (Rr x RR), what genotypic proportions would be observed in the offspring?

		Half heterozygous, half homozygous dominant
		Half round, half wrinkled
		All heterozygous
		All round

Question 10

What would be the dimensions of a Punnett Square depicting a dihybrid cross?

		1 x 4
		2 x 4
		4 x 4
		2 x 2

BIOL 204 Chapter Notes - Chapter 2: Mendelian Inheritance, Zygosity, Germination

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