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Department
Chemistry
Course
CAS CH 131
Professor
Mark Grinstaff
Semester
Fall

Description
Oxidation Number Determination Cr(OH)3= 3Cr^3+ OH­ Br2=2Br CrO4^2­ + [Cr^6+ 4O^2­]^2­ Half Reactions Cr^3+ = Cr^6+ + 3E­ Br2 +2E­  ▯2 Br Combine and Balance to form: 2Cr^3+ + 3Br2  ▯2 CR^6+ + 6Br Colligative Properties 500g of Diethyl ether (74.0 g/mol) is in a flask at 30C. Its normal vapor pressure is .83  ATM above the liquid. If 65 g sodium benzoate (NaC6H5CO2 154 g/mol) dissolves in  diethyl ether, what is the vapor pressure of diethyl ether above? New vapor pressure = mole fraction of solvent*pure vapor pressure of solvent  Mole fraction of solvent = moles of solvent/total moles of solution Moles of solvent = 6.7 moles Moles of solute = .422 moles Moles of solute in solution = .844 moles  6.7 moles of solvent/(6.7 +.844) = .89 mole fraction of solvent .89*.83 ATM= .7 ATM What if 65 g of hexane (86 g/mole) was added instead of sodium benzoate. What is the  total vapor pressure above the solution? (hexane is volatile) So the pure pressure o
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