CE 2200 Chapter : Homework 8

11 views21 pages
15 Mar 2019
School
Course
Professor

Document Summary

Problem-5: solution: finally, we can find the discharge by inserting our result for the flow velocity into the flow rate equation: Find: discharge, hgl, egl, locations of maximum and minimum pressure, values for the maximum and minimum pressure. Properties: the specific weight of water at 10oc is 9804 n/m3. Assumptions: (1) the flow is steady and incompressible. (2) velocity distribution in the pipe is uniform ((cid:68)=1). Taking reservoir water surface as pint 1 and jet exit as point 2 and applying the energy equation yields p. L where hp = 0, ht = 0, p1 = p2 = 0 (atmospheric pressure), v1 = 0, z1 = 100 m, z2 = 30 m. Substitution of the known values into the energy equation gives (cid:167) (cid:183) (cid:168) (cid:184) (cid:168) (cid:185) (cid:169) (cid:167) (cid:168) Based on the continuity equation v2a2 = vpap or.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related Documents

Related Questions