MAC1106 Chapter Notes - Chapter 6: Exponentiation, Precalculus, Motorola 68020

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Let both f and g be functions with overlapping domains. Di erence (f + g) (x) = f (x) + g (x) Example : f (x) = 2x + 4 g (x) = 6x + 6 (f + g) (x) (f + g) (x) = 8x + 10 (f g) (x) = f (x) g (x) Example : f (x) = 2x + 4 g (x) = 6x + 6 (f g) (x) (f g) (x) = (2x + 4) (6x + 6) = (2 6)x + (4 6) Quotient (f g) (x) = f (x) g (x) = 12x2 + (12 + 24)x + 24. = 12x2 + 36x + 24 g(cid:17) (x) = (cid:16) f (x) (cid:16) f g(x)(cid:17) (x) = f (x) g(x) , g (x) 6= 0. Example : f (x) = 2x + 4 g (x) = 6x + 6 (cid:16) f g(cid:17) (x) g(cid:17) (x) (cid:16) f.

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