CHEM 001C Lecture Notes - Lecture 8: Acid Dissociation Constant, Sodium Hydroxide

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5 May 2018
Department
Course
Professor
CHEM 001C Lecture 8: Midterm 1 Review Chapters 13-15
Dynamic Equilibrium
Do strong acids or bases exhibit equilibrium?
HCl → H+ + Cl-
NaOH → Na+ + OH-
No; they completely dissociate (no reactants left)
Amphoteric
Amphoteric: can act as an acid or base
Ka
What does Ka mean?
Acid dissociation constant
How likely an acid is to dissociate
pKa < 1 → stronger acid → larger Ka
Example: Calculate the pH of a solution of 1.00 M HCN and 5.00 M HNO2
HCN + H2O H3O+ + CN- Ka = 6.2 x 10-10
HNO2 + H2O H3O+ + NO2
-Ka = 4.0 x 10-4
H2O + H2O H3O+ + OH-Kw = 1.0 x 10-14
HNO2 will dissociate the most: produce the most products
HNO2(aq)
H2O(l)
H+(aq)
NO2
-(aq)
5.00 M
-
0
0
-x
-
+x
+x
5.00-x
-
x
x
Ka = 4.0 x 10-4 =
x2
5.00 −x
x2
5.00
x = 4.5 x 10-2 = [H+]
pH = 1.35
pH with HCN and HNO2 = 1.346
K value is so small for the other two, the
effect on equilibrium concentration is so
small (not noticed)
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Document Summary

Chem 001c lecture 8: midterm 1 review chapters 13-15. No ; they completely dissociate (no reactants left) Amphoteric : can act as an acid or base. How likely an acid is to dissociate. Pk a < 1 stronger acid larger k a. Example : calculate the ph of a solution of 1. 00 m hcn and 5. 00 m hno 2. Hcn + h 2 o h 3 o + + cn - k a = 6. 2 x 10 -10. Hno 2 + h 2 o h 3 o + + no 2 . H 2 o + h 2 o h 3 o + + oh - Hno 2 will dissociate the most: produce the most products. X = 4. 5 x 10 -2 = [h + ] Ph with hcn and hno 2 = 1. 346. K value is so small for the other two, the effect on equilibrium concentration is so small (not noticed)