Textbook ExpertVerified Tutor
5 Nov 2021
Given information
Here, Sample size(n)=100;
The lowest actual weight=24, and the highest actual weight=26;
Step-by-step explanation
Step 1.
So, from the given information,
mean of the distribution (μx)=(24+26)/2=25;
So,
& standard deviation(σx);
σx=0.5774;
So,
So, the distribution for the mean weight of 100 25-pound liftings weight=
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