mauvemule811Lv1
6 Dec 2021
Problem 21a
Page 412
Section 5.9: Approximate Integration
Chapter 5: Integrals
Textbook ExpertVerified Tutor
6 Dec 2021
Given information
The given integral is 
where 
Step-by-step explanation
Step 1.
Using a CAS, we differentiate twice, and find that
twice, and find that
at 
Since 
,
,
Single Variable Calculus: Early Transcendentals
4th Edition, 2018
Stewart
ISBN: 9781337687805
Solutions
Chapter
Section
- Problem 1a
- Problem 1b
- Problem 1c
- Problem 1d
- Problem 2a
- Problem 2b
- Problem 3
- Problem 4a
- Problem 4b
- Problem 4c
- Problem 5
- Problem 6
- Problem 7
- Problem 8
- Problem 9
- Problem 10
- Problem 11
- Problem 12
- Problem 13
- Problem 14
- Problem 15
- Problem 16
- Problem 17a
- Problem 17b
- Problem 17c
- Problem 18a
- Problem 18b
- Problem 18c
- Problem 19a
- Problem 19b
- Problem 19c
- Problem 20
- Problem 21a
- Problem 21b
- Problem 21c
- Problem 21d
- Problem 21e
- Problem 21f
- Problem 21g
- Problem 21h
- Problem 21i
- Problem 21j
- Problem 22
- Problem 22b
- Problem 23
- Problem 24
- Problem 25
- Problem 25
- Problem 26
- Problem 26
- Problem 27a
- Problem 27b
- Problem 27c
- Problem 28
- Problem 29
- Problem 30
- Problem 31
- Problem 32
- Problem 33a
- Problem 33b
- Problem 34
- Problem 35
- Problem 35
- Problem 36
- Problem 37
- Problem 38
- Problem 39
- Problem 40
- Problem 41
- Problem 42