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Lecture 7

Lecture 7.docx

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Carleton University
PSYC 2700
Chris Herdman

Lecture 7 Retrieval from STS Strenberg scanning task - Quest • Time to make one mental comparison (in STS)? - Task • Memory search (scanning) • Asked if the probe was part of the memory set - How to model? • Assume: time between a stimulus and a response is occupied by a series of DISCRETE STAGES  Probe digit (#3)  Encoding stage  Encode into sensory memory  Memory comparison stage  Compare the probe item to the items in memory  1 memory comparison = ~38ms  Response output stage  Push the yes or no button • The information flows from 1 stage to the other. Only one is active at a time. - Three hypotheses regarding search in STS • Parallel  Search occurs in parallel, meaning all at once  Maybe when the probe item comes up, our system compares the probe item against all given numbers at the same time  Most efficient • Serial self-terminating  Less efficient than parallel, but still good  Serial means one after the other  If you find a match, you stop looking • Serial exhaustive  Always try to match probe withALL the numbers from the set.Always go to the very end  Most inefficient way - Support: serial exhaustive search in STS is what we use Additive factors logic and modeling - Nature of representations being compared? • Same task (memory probe task) • Clear vs. degraded probe digit  Degraded by lowering contrast of the probe item • Encoding or memory comparison? Encoding stage - Probe digit - Encoding stage - Memory comparison stage • Compare 1 ~38ms • Compare 2 ~38ms • Compare 3 ~38ms • Compare n ~38ms - Response output stage Encoding stage locus predicts additivity - Clear vs. degraded • Asks for a little bit of extra time to clear up a degraded probe • Set size doesn’t matter - This stage cleans up the probe item before sending it along the line - Adding a constant Memory stage - Probe digit - Encoding stage - Memory comparison stage • Compare 1 38ms (normally) + 12ms = 50ms • Compare 2 38ms + 12ms = 50ms • Compare 3 38ms + 12ms = 50ms • Compare n 38ms + 12ms = 50ms - Response output stage Memory stage locus predicts interaction - Adding a constant to each comparison (+12ms) results in an interaction between clear and degraded. See them separating out. - Each comparison takes more time with a degraded stimulus Actual results Summary of additive factors logic - Advantages • Simple logic used to isolate stages in a serial process - Disadvantage • Only useful when examining a simple serial process.Assume discrete stages Lev
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